当我使用G++编译器的时候
用到了cmath中的pow函数~~

x=pow(2,3);

结果就出了一大堆错误，郁闷啊

把错误信息给大家看一下，希望大家给个意见~

79006\Main.cc:14: error: call of overloaded `pow(int, int&)' is ambiguous
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/math.h:150: note: candidates are: double pow(double, double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:361: note: long double std::pow(long double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:357: note: float std::pow(float, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:353: note: double std::pow(double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:349: note: long double std::pow(long double, long double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:345: note: float std::pow(float, float)
79006\Main.cc:17: error: call of overloaded `pow(int, int&)' is ambiguous
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/math.h:150: note: candidates are: double pow(double, double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:361: note: long double std::pow(long double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:357: note: float std::pow(float, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:353: note: double std::pow(double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:349: note: long double std::pow(long double, long double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:345: note: float std::pow(float, float)
79006\Main.cc:24: error: call of overloaded `pow(int, int&)' is ambiguous
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/math.h:150: note: candidates are: double pow(double, double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:361: note: long double std::pow(long double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:357: note: float std::pow(float, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:353: note: double std::pow(double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:349: note: long double std::pow(long double, long double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:345: note: float std::pow(float, float)

但是在VC6.0中就完全正确~~
不解啊~~~

据说pow()换成pow<double>()就行

G++对类型的要求比较严格，你的调用产生了二义性，可以使用强制转换

如
int a,b;
pow(a,b) 可改成 pow(long double(a),b)

[此贴子已经被作者于2007-10-25 8:20:15编辑过]

x=pow(2.0,3.0);

应该是这个编译器的类型检查更严格.

好像不行~~改了之后依然会有错无~~

79034\Main.cc: In function `int main()':
79034\Main.cc:17: error: no matching function for call to `pow(int, int&)'
79034\Main.cc:20: error: no matching function for call to `pow(int, int&)'
79034\Main.cc:27: error: call of overloaded `pow(int, int&)' is ambiguous
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/math.h:150: note: candidates are: double pow(double, double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:361: note: long double std::pow(long double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:357: note: float std::pow(float, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:353: note: double std::pow(double, int)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:349: note: long double std::pow(long double, long double)
bin/gcc/bin/../lib/gcc/mingw32/3.4.2/../../../../include/c++/3.4.2/cmath:345: note: float std::pow(float, float)

G++对类型的要求比较严格，你的调用产生了二义性，可以使用强制转换

如
int a,b;
pow(a,b) 可改成 pow(long double(a),b)

我现在的问题是这样~

int x=2, y=3;

pow( x,y )

这样的话该怎样改呢？？

强制类型转换

pow(long double(x),y)

我也遇到过，干脆自己写一个int pow(int,int)函数算了，也不难。
int pow(int a,int b){
int s=1;
for(int i=0,i<b,i++)s= s* a;
return s;
}

我晕了~~还不行.....................
我把我的代码帖上来吧~~~
[CODE]
/*---------------------------------------------------------------

Description

　　集合的前N个元素：编一个程序，按递增次序生成集合M的最小的N个数，M的定义如下：
(1)数1属于M；
(2)如果X属于M，则Y=2*X+1和Z=3*x+1也属于M；
(3)此外再没有别的数属于M。

Input

n(b.in) （1≤n≤100）

Output

生成集合M的最小的N个数(b.out)

Sample Input

4

Sample Output

1 3 4 7

-----------------------------------------------------------------*/

#include<iostream>
#include<algorithm>
#include<vector>
#include<cmath>
using namespace std;

int main()
{
int num, i, j, k;
cin>>num;

int sum=0;
for( i=0; num > sum; i++ )
sum = sum + pow(2.0,double(i));

k=i-1;
int *p=new int [pow(2.0,double(k))];
vector< int > vec;

p[0]=1, vec.push_back(1);

for( i=1; i<=k; i++ )
{
for( j=pow(2,i)-1; j>=0; j--)
{
if( j % 2 !=0 )
p[j] = 3 * p[j/2] + 1;

else
p[j] = 2 * p[j/2] + 1;

vec.push_back( p[j] );
}
}

sort( vec.begin(), vec.end() );

for( i=0; i<num; i++ )
cout<<vec[i]<<" ";

cout<<endl;

return 0;
}



[/CODE]