这是我的代码
#include<stdio.h>
int main()
{
int i,a[10000],b[10000];
for(i=1;i<=10;i++)
{
scanf("%d",&a[i]);
if(a[i]==0)
break;
}
for(int k=1;k<i;k++)
b[k]=a[k];
for(int j=1;j<=i-1;j++)
{
if((b[j]-6)%4==0)
{
printf("%d is the sum of four consecutive integers.\n",b[j]); }
else
{
printf("%d]is not the sum of four consecutive integers.\n",b[j]); }

}
return 1;
}
这是题目
Input
A positive integer(<2³¹), each case will be on a separate line. A zero (0) denotes the end of input.
Output
The phrase “ is not the sum of four consecutive integers.” or the phrase “ is the sum of four consecutive integers.”, where is the number in question.
Example
In this example, 2 = -1 + 0 + 1 + 2, and 82 = 19 + 20 + 21 + 22. 5 and 41 are not of the correct form.
Input
5
41
82
0
Output
2 is the sum of four consecutive integers.
5 is not the sum of four consecutive integers.
41 is not the sum of four consecutive integers.
82 is the sum of four consecutive integers.

1、A zero (0) denotes the end of input.你忘记看这句了

2、2的31次方超过int的范围了，用long类型（long的范围多少我也不记得了，或者应该用无符号的long）

3、何必从数组a复制到b呢？

4、判断的话用a[i]%4==2判断就好了

#include <stdio.h>
char* str[]={\" is not the sum of four consecutive integers.\",
             \" is the sum of four consecutive integers.\"};
int main()
{
    int n;
    while(scanf(\"%d\",&n),n){
        printf(\"%d%s\n\",n,str[n%4==2]);
    }    
}