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标题:vb.net程序注册的客户端源码,请求帮助如何反向做出加密文件的程序
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jk1963
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vb.net程序注册的客户端源码,请求帮助如何反向做出加密文件的程序

Public Shared Function jiekai() As Object
Dim num As Integer
Dim num2 As Integer
Dim num3 As Integer
Dim num4 As Integer
Dim time As DateTime
Dim numArray As Integer() = New Integer(30) {}
Dim numArray2 As Integer() = New Integer(30) {}
Dim numArray3 As Integer() = New Integer(30) {}

Dim str2 As String = "4mt1jx14" '这是计算密码文件用的客户端序列号

Dim str3 As String = str2

numArray(17) = (Strings.Asc(str2.Substring(0, 1)) * 175)
numArray(8) = (Strings.Asc(str2.Substring(1, 1)) * 175)
numArray(2) = (Strings.Asc(str2.Substring(2, 1)) * 175)
numArray(20) = (Strings.Asc(str2.Substring(3, 1)) * 175)
numArray(23) = (Strings.Asc(str2.Substring(4, 1)) * 175)
numArray(12) = (Strings.Asc(str2.Substring(5, 1)) * 175)
numArray(1) = (Strings.Asc(str2.Substring(6, 1)) * 175)
numArray(9) = (Strings.Asc(str2.Substring(7, 1)) * 175)
numArray(6) = (Strings.Asc(str2.Substring(8, 1)) * 175)
numArray(10) = (Strings.Asc(str2.Substring(9, 1)) * 175)
numArray(5) = (Strings.Asc(str2.Substring(10, 1)) * 175)
numArray(7) = (Strings.Asc(str2.Substring(11, 1)) * 175)
numArray(4) = (Strings.Asc(str2.Substring(0, 1)) * 175)
numArray(19) = (Strings.Asc(str2.Substring(1, 1)) * 175)
numArray(22) = (Strings.Asc(str2.Substring(2, 1)) * 175)
numArray(24) = (Strings.Asc(str2.Substring(3, 1)) * 175)
numArray(11) = (Strings.Asc(str2.Substring(4, 1)) * 175)
numArray(15) = (Strings.Asc(str2.Substring(5, 1)) * 175)
numArray(21) = (Strings.Asc(str2.Substring(6, 1)) * 175)
numArray(3) = (Strings.Asc(str2.Substring(7, 1)) * 175)
numArray(18) = (Strings.Asc(str2.Substring(8, 1)) * 175)
numArray(14) = (Strings.Asc(str2.Substring(9, 1)) * 175)
numArray(13) = (Strings.Asc(str2.Substring(10, 1)) * 175)
numArray(16) = (Strings.Asc(str2.Substring(11, 1)) * 175)
numArray3(1) = 412231
numArray3(2) = 463868
numArray3(3) = 676596
numArray3(4) = 209182
numArray3(5) = 79209
numArray3(6) = 32873
numArray3(7) = 291191
numArray3(8) = 568813
numArray3(9) = 29497
numArray3(10) = 54939
numArray3(11) = 201155
numArray3(12) = 391652
numArray3(13) = 521732
numArray3(14) = 65165
numArray3(15) = 95221
numArray3(16) = 15542
numArray3(17) = 18370
numArray3(18) = 92649
numArray3(19) = 46179
numArray3(20) = 4865
numArray3(21) = 2383
numArray3(22) = 28756
numArray3(23) = 19428
numArray3(24) = 34153
FileSystem.FileOpen(1, ("d:\101\mima.pas"), OpenMode.Random, OpenAccess.Default, OpenShare.Default, 20) '随机访问打开密码文件
Module1.mi(1) = FileSystem.FileLen("d:\101\mima.pas")

If (Module1.mi(1) > 1500) Then
Dim num5 As Integer
Dim type As ValueType
num = 1
Do
num5 = num
type = Module1.mima_insert(num5)
FileSystem.FileGet(1, type, -1)
Module1.mima_insert(num5) = DirectCast(type, mima_insert_type)
num += 1
Loop While (num <= 17)
type = Module1.mima_time1
FileSystem.FileGet(1, type, -1)
Module1.mima_time1 = DirectCast(type, Module1.mima_time_type)
num2 = (Module1.mima_time1.t - Module1.mima_insert(9).c2)
num = 1
Do
Select Case num
Case 11
type = Module1.mima_time2
FileSystem.FileGet(1, type, -1)
Module1.mima_time2 = DirectCast(type, Module1.mima_time_type)
num3 = (Module1.mima_time2.t - Module1.mima_insert(3).c2)
Exit Select
Case 22
type = Module1.mima_time3
FileSystem.FileGet(1, type, -1)
Module1.mima_time3 = DirectCast(type, Module1.mima_time_type)
num4 = (Module1.mima_time3.t - Module1.mima(15).c2)
Exit Select
End Select
num5 = num
type = Module1.mima(num5)
FileSystem.FileGet(1, type, -1)
Module1.mima(num5) = DirectCast(type, Module1.mima_type)
num += 1
Loop While (num <= 24)
End If

FileSystem.FileClose(New Integer() {1})
Dim dateValue As String = String.Concat(New String() {Conversions.ToString(2), Conversions.ToString(0), Conversions.ToString(0), Conversions.ToString(4), "/", Conversions.ToString(1), Conversions.ToString(2), "/", Conversions.ToString(3), Conversions.ToString(0)})
If ((num2 = num3) And (num3 = num4)) Then
time = DateAndTime.DateAdd("d", CDbl(num2), dateValue)
Else
time = Module1.gust_ut
End If

num = 1
Do
numArray2(num) = ((numArray3(num) - Module1.mima(num).c1) + Module1.mima(num).c2)
num += 1
Loop While (num <= 24)
num = 1
Do
If (numArray(num) <> numArray2(num)) Then
time = Module1.gust_ut
num = 100
End If
num += 1
Loop While (num <= 24)
Return time
End Function

Public Structure mima_insert_type
Public c1 As Integer
Public c2 As Integer
End Structure


Public Structure mima_time_type
Public t As Integer
End Structure


Public Structure mima_type
Public c1 As Integer
Public c2 As Integer
End Structure

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2007-09-25 21:11
qlong0728
Rank: 3Rank: 3
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注 册:2007-6-15
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假如是我做
户端序列号就是自动获取硬盘序列号
再根据序列号每一位加几或剩几后转成一个ASC码,一个循环就可以了。

如果别人不知加密思路,是很难破解的。




程序人员写程序,又拿程序换酒钱。 奔驰宝马贵者趣,公交自行程序员。 不见满街漂亮妹,哪个归得程序员。
2007-09-25 22:01
快速回复:vb.net程序注册的客户端源码,请求帮助如何反向做出加密文件的程序
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