#include "stdafx.h"
#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main(int argc, char* argv[])
{
vector<int>str;
str.push_back(3);
str.push_back(3);
str.push_back(2);
str.push_back(7);
sort(str.begin(),str.end());
vector<string>::iterator it;
for(it=str.begin();it!=str.end();it++)
{
cout<<*it;
}
return 0;

}

谁知道我的有什么错误啊调试不过，这个怎么输出阿

对不起，这样

#include "stdafx.h"
#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main(int argc, char* argv[])
{
vector<string>str;
str.push_back("aaa");
str.push_back("bbb");
str.push_back("wrer");
str.push_back("asldf");
sort(str.begin(),str.end());
vector<string>::iterator it;
for(it=str.begin();it!=str.end();it++)
{
//这里怎样输出阿
}
return 0;
}

#include "stdafx.h"
#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main(int argc, char* argv[])
{
vector<string>str;
str.push_back("aaa");
str.push_back("bbb");
str.push_back("wrer");
str.push_back("asldf");
sort(str.begin(),str.end());
vector<string>::iterator it;
for(it=str.begin();it!=str.end();it++)
{
cout<<(*it);
}
return 0;
}

error C2679: binary '<<' : no operator defined which takes a right-hand operand of type 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' (or there is no acceptable conversion)

可是它抱错啊像上面

[此贴子已经被作者于2007-8-3 21:43:21编辑过]