编写一个程序首先输出提示 "do you want to continue?"，然后读取用户输入。如果用户输入为“y","yes","ok","sure","why not",则输出“ok";如果用户输入的是"n","not"则输出”not" 否则输出"input error"不区分大小写！
在线等待1!

简化了对用户输入的判断，需要的话，LZ自己修改一下吧！（VC6.0通过）

#include<iostream>
#include<string>
using namespace std ;

void main()
{
string IsContinue ;

cout << "do you want to continue? " ;
cin >> IsContinue ;

if(IsContinue == "y" || IsContinue == "Y")
cout << "ok" << endl ;
else if(IsContinue == "n" || IsContinue == "N")
cout << "not" << endl ;
else
cout << "input error!" << endl ;
}

[此贴子已经被作者于2007-7-24 16:59:07编辑过]

谢谢！

怎么到我这里就提示错误啊
error C2040: '==' : 'int' differs in levels of indirection from 'char [2]'

#include <iostream.h>
#include <string.h>
using namespace std;

int main()
{
string IsContinue;
cout<<"do you want to continue?"<<endl;
cin>>IsContinue;
if (IsContinue == "y" || IsContinue == "Y")
{
cout<<"ok"<<endl;
}
else if (IsContinue == "n" || IsContinue == "N")
{
cout<<"not"<<endl;
}
else
{
cout<<"input error!"<<endl;
}
return 0;
}