This is an annoying problem. How do you handle the newline char '\n' in the input stream?

Although my C++ code was accepted, I am not satisfied --- I used cin.peek(). So the qeustion remains to be

1. Can you do it in C?
2. Can you do it without using cin.peek() and/or putback()?

Note that there maybe more than one spaces between two numbers, and there maybe 0 or more spaces before '\n'.


Problem statement:

http://acm.nankai.edu.cn/p1023.html

对于输入的数据进行求和。

Input
输入有多行数据，每行有若干整数，这些整数数以空格分割，请分别求出每行整数的和。

Output
输出的每行对应输入的每行，每行一个数字，即为输入的一行整数之和。

Sample Input
100 200 4
45 45

Sample Output
304
90

[此贴子已经被作者于2007-7-19 8:02:19编辑过]

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
    int n,res;
    char buf[10000],*p;
    while(gets(buf)){
        sscanf(strtok(buf,\" \n\"),\"%d\",&res);
        while(p=strtok(NULL,\" \n\")){
            sscanf(p,\"%d\",&n);
            res+=n;
        }    
        printf(\"%d\n\",res);
    }
}

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
    int n,res;
    char buf[10000],*p;
    while(gets(buf)){
        sscanf(strtok(buf,\" \n\"),\"%d\",&res);
        while(p=strtok(NULL,\" \n\")){
            sscanf(p,\"%d\",&n);
            res+=n;
        }    
        printf(\"%d\n\",res);
    }
}

very smart soln --- thought there is some obvious solution, but it seems it is not that obvious.

Here is my C++ version (I thought those who are interested in this problem already tried it)

#include <iostream>
using namespace std;

int main()
{
    int a, sum=0;
    while( cin>> a )
    {
        sum += a;
        while(cin.peek() == ' ')
            getchar();
        if(cin.peek() == '\n')
        {
            cout<<sum<<endl;
            sum = 0;
        }
    }
    return 0;
}

[此贴子已经被作者于2007-7-20 13:54:40编辑过]

要是大数相加我还不做了来 嫌麻烦！