#include<stdio.h>
void week_several(void);
void dates(void);
void Is_leapyear(int year);
main()
{ int num;
printf(" MENU");
printf("1.Inquires some year, month and day is the week several\n");
printf("2.Inquires some year whether is the leap year\n");
printf("3.Prints some year the whole year calendar\n");
printf("4.Exit\n");
printf("Please choose a number:");
scanf("%d",&num);
switch(num)
{case 1: dates();break;
case 2: break;
case 3:
case 4: break;
default: printf("Your input is not correct, please choose again");
}
/*主函数*/

void dates(void)
{int year,month,day,week_several;
printf("Please give the date you want to inquire");
scanf("%d%d%d",&year,&month,&day);
prinf("the date you inquire is:%s",week_several(year,month,day));
}
/*查询星期几的主函数*/

void week_several(long year,long month,long day)
{int i,j,k,week_day,days=0;
for(i=1900;i<year;i++)
{if(Is_leapyear(i)) days+=366;
else days+=365;
}
/*计算年份天数*/
for(j=1;j<month;j++)
{switch(j)
{case 2:if(Is_leapyear(year)) days+=29;
else days+=28; break;
case 4: case 6: case 9: case 11: days+=30; break;
default: days+=31; break;
}
}
/*计算月份天数*/
for(k=1;k<=day;k++)
days++;
/*计算总天数 */
week_day=days%7;
switch(week_day)
{case 1: return("Monday"); break;
case 2: return("Tuesday"); break;
case 3: return("Wednesday"); break;
case 4: return("Thusday"); break;
case 5: return("Friday"); break;
case 6: return("Saturday"); break;
case 0: return("Sunday"); break;
}
}

void Is_leapyear(int year) /*判断闰年*/
{return(year%4==0&&year%100!=0||year%400==0)}

程序没写完 但
里面两个报错 ：
void dates(void)报错 expression syntax in function
最后一行报错 少了个}

帮忙哦

我就看了下你最后的代码　
void Is_leapyear(int year) /*判断闰年*/
{return(year%4==0&&year%100!=0||year%400==0)}　　//这个地方你少了个；　

#include<stdio.h>
void week_several(void);//后面写的函数带了3个参数,并且返回不可能是空
void dates(void);
void Is_leapyear(int year); //类型
main()
{ int num;
printf(" MENU");
printf("1.Inquires some year, month and day is the week several\n");
printf("2.Inquires some year whether is the leap year\n");
printf("3.Prints some year the whole year calendar\n");
printf("4.Exit\n");
printf("Please choose a number:");
scanf("%d",&num);
switch(num)
{case 1: dates();break;
case 2: break;
case 3:
case 4: break;
default: printf("Your input is not correct, please choose again");
}
/*主函数*/

void dates(void)
{int year,month,day,week_several;
printf("Please give the date you want to inquire");
scanf("%d%d%d",&year,&month,&day);
prinf("the date you inquire is:%s",week_several(year,month,day));//printf写错
}
/*查询星期几的主函数*/

void week_several(long year,long month,long day)//参数和上面输入的参数类型不同int ->long了
{int i,j,k,week_day,days=0;
for(i=1900;i<year;i++)
{if(Is_leapyear(i)) days+=366;
else days+=365;
}
/*计算年份天数*/
for(j=1;j<month;j++)
{switch(j)
{case 2:if(Is_leapyear(year)) days+=29;
else days+=28; break;
case 4: case 6: case 9: case 11: days+=30; break;
default: days+=31; break;
}
}
/*计算月份天数*/
for(k=1;k<=day;k++)
days++;
/*计算总天数 */
week_day=days%7;
switch(week_day)
{case 1: return("Monday"); break;
case 2: return("Tuesday"); break;
case 3: return("Wednesday"); break;
case 4: return("Thusday"); break;
case 5: return("Friday"); break;
case 6: return("Saturday"); break;
case 0: return("Sunday"); break;
}
}

void Is_leapyear(int year) /*判断闰年*/
//肯定要返回0或1进行上面的判断么
{return(year%4==0&&year%100!=0||year%400==0)}//少;

我按楼上说的将错误改了下
但还是同样的报错
为什么呀 郁闷~~·

#include<stdio.h>
void week_several(int ,int ,int);
void dates(void);
void Is_leapyear(int year);
main()
{ int num;
printf(" MENU");
printf("1.Inquires some year, month and day is the week several\n");
printf("2.Inquires some year whether is the leap year\n");
printf("3.Prints some year the whole year calendar\n");
printf("4.Exit\n");
printf("Please choose a number:");
scanf("%d",&num);
switch(num)
{case 1: dates();break;
case 2: break;
case 3:
case 4: break;
default: printf("Your input is not correct, please choose again");
}
/*主函数*/

void dates(void)
{int year,month,day,week_several;
printf("Please give the date you want to inquire");
scanf("%d%d%d",&year,&month,&day);
printf("the date you inquire is:%s",week_several(year,month,day));
}
/*查询星期几的主函数*/

void week_several(int year,int month,int day)
{int i,j,k,week_day,days=0;
for(i=1900;i<year;i++)
{if(Is_leapyear(i)) days+=366;
else days+=365;
}
/*计算年份天数*/
for(j=1;j<month;j++)
{switch(j)
{case 2:if(Is_leapyear(year)) days+=29;
else days+=28; break;
case 4: case 6: case 9: case 11: days+=30; break;
default: days+=31; break;
}
}
/*计算月份天数*/
for(k=1;k<=day;k++)
days++;
/*计算总天数 */
week_day=days%7;
switch(week_day)
{case 1: return("Monday"); break;
case 2: return("Tuesday"); break;
case 3: return("Wednesday"); break;
case 4: return("Thusday"); break;
case 5: return("Friday"); break;
case 6: return("Saturday"); break;
case 0: return("Sunday"); break;
}
}

void Is_leapyear(int year) /*判断闰年*/
{return(year%4==0&&year%100!=0||year%400==0);}

有没有大家HELP HELP 啊 ~ 没时间咯哦

void Is_leapyear(int year) /*判断闰年*/
{return(year%4==0&&year%100!=0||year%400==0);}

void 你还return??!
建议把void 该为int 或者bool

void dates(void)//此处把函数定义括号里的void去掉
{int year,month,day,week_several;
printf("Please give the date you want to inquire");
scanf("%d%d%d",&year,&month,&day);
printf("the date you inquire is:%s",week_several(year,month,day));
}
/*查询星期几的主函数*/

很郁闷 我再次修改以后还是报错两个
估计我得重写这个程序
可是写来写去还是这么想的~

刚仔细再次修改了下
#include<stdio.h>
void week_several(int ,int ,int);
void dates()；
int Is_leapyear(int);
main()
{int num;
printf(" MENU");
printf("1.Inquires some year, month and day is the week several\n");
printf("2.Inquires some year whether is the leap year\n");
printf("3.Prints some year the whole year calendar\n");
printf("4.Exit\n");
printf("Please choose a number:");
scanf("%d",&num);
switch(num)
{case 1: dates();break;
case 2: break;
case 3:
case 4: break;
default:printf("Your input is not correct, please choose again");
}
}
/*主函数*/

void dates()
{int year,month,day;
printf("Please give the date you want to inquire");
scanf("%d%d%d",&year,&month,&day);
printf("the date you inquire is:%s",week_several(year,month,day));
}
/*查询星期几的主函数*/

void week_several(int year,int month,int day)
{int i,j,k,week_day,days=0;
for(i=1900;i<year;i++)
{if(Is_leapyear(i)) days+=366;
else days+=365;
}
/*计算年份天数*/
for(j=1;j<month;j++)
{switch(j)
{case 2:if(Is_leapyear(year)) days+=29;
else days+=28; break;
case 4: case 6: case 9: case 11: days+=30; break;
default: days+=31; break;
}
}
/*计算月份天数*/
for(k=1;k<=day;k++)
days++;
/*计算总天数 */
week_day=days%7;
switch(week_day)
{case 1: return("Monday"); break;
case 2: return("Tuesday"); break;
case 3: return("Wednesday"); break;
case 4: return("Thusday"); break;
case 5: return("Friday"); break;
case 6: return("Saturday"); break;
case 0: return("Sunday"); break;
}
}

int Is_leapyear(int year) /*判断闰年*/
{return(year%4==0&&year%100!=0||year%400==0);}


现在程序这样了 又有了一个新的错误：
第29行 NOT an allowed type in fuction dates

那应该怎么改呢 我是新手很麻烦 见谅啊~

看这句:printf("the date you inquire is:%s",week_several(year,month,day));

年是要把week_several以%S的方式输出吧``` `

但是你把week_several定义为void```也就是说``week_several是空类型的``没有任何值``

那么这个时候%S和week_several的类型就不匹配```

那我应该怎么改呢？