实现strcat的功能！运行后得不到结果～！


#include "stdio.h"
void connect(char a[],char b[],char c[])
{int i,j;
for(i=0;a[i]!='\0';i++)
c[i]=a[i];
for(j=0;b[j]!='\0';j++)
c[i+j]=b[j];
c[i+j]='\0';
return;
}
main()
{char a[100],b[100],c[200];
printf("input string1:");
scanf("%s",a);
printf("input string2:");
scanf("%s",b);
connect(a,b,c);
}

[此贴子已经被作者于2007-5-3 9:57:42编辑过]

没输出啊.

#include "stdio.h"
void connect(char a[],char b[],char c[])
{int i,j;
for(i=0;a[i]!='\0';i++)
c[i]=a[i];
for(j=0;b[j]!='\0';j++)
c[i+j]=b[j];
c[i+j]='\0';

return;
}
main()
{char a[100],b[100],c[200];
printf("input string1:");
scanf("%s",a);
printf("input string2:");
scanf("%s",b);
connect(a,b,c);
printf("%s\n",c); //加上这个输出语句就可以看到结果啦
}

[CODE]

#include <stdio.h>

int con (char a[], char b[], char c[]);

int main(void)
{
char a[100], b[100], c[100];
printf ("input string1:");
gets (a);
printf ("input string2:");
gets (b);
con (a, b, c);
puts (c);

return 0;
}

int con (char a[], char b[], char c[])
{
int i, j;

for (i = 0;a[i] !='\0';i ++)
{
c[i] = a[i];
}
for (j = 0;b[j] != '\0';j ++)
{
c[i + j] = b[j];
}
c[i + j + 1] = '\0';

return 0;
}

[/CODE]

#include "stdio.h"
void connect(char a[],char b[],char c[])
{int i,j;
for(i=0;a[i]!='\0';i++)
c[i]=a[i];
for(j=0;b[j]!='\0';j++)
c[i+j]=b[j];
c[i+j]='\0';
return;
}
main()
{char a[100],b[100],c[200];
printf("input string1:");
scanf("%s",a);
printf("input string2:");
scanf("%s",b);
connect(a,b,c);
printf("%s\n",c);
}

知道了,顺便谢谢各位大虾,我也长知识了....