#include<iostream.h>
#include<math.h>
class Point
{
public:
Point(double a,double b,double c)
{ x=a;y=b;z=c; };
Point(Point &p);
void negate(double e,double f,double g)
{
x=-e;
y=-f;
z=-g;

}
double norm(double k,double l,double m)
{
double r;
x=k;y=l;z=m;
r=sqrt(x*x+y*y+z*z);
return (r);
}
void print();
~Point(){}
private:
double x,y,z;
};
Point::Point(Point &p)
{
x=p.x;
y=p.y;
z=p.z;
}
void Point::print()
{
cout<<"x="<<x<<" "<<"y="<<y<<" "<<"z="<<z<<endl;
}
double main()
{
Point A(3.00,4.00,5.00);
Point B(A);
B.print();
double destance=A.norm();
cout<<"destance:"<<destance<<"\n";
return 0;
}



我想让它,;输出,negate()是把这个点按照原点对称变换的函数,norm()是求到原点的距离,
请问要怎样改.....

你想让它输出什么呢?好象没有说清楚呢?

程序的作用没有说清楚!

#include<iostream>
#include<math.h>
using namespace std;
class Point
{
public:
Point(double a,double b,double c)
{ x=a;y=b;z=c; };
Point(Point &p);
void negate()
{
x=-x;
y=-y;
z=-z;

};
double norm()
{
double r;
r=sqrt(x*x+y*y+z*z);
return (r);
};
void print();
private:
double x,y,z;
};
Point::Point(Point &p)
{
x=p.x;
y=p.y;
z=p.z;
}
void Point::print()
{
cout<<"x="<<x<<" "<<"y="<<y<<" "<<"z="<<z<<endl;
}
void main()
{
Point A(3.00,4.00,5.00);
Point B(A);
B.print();
double destance=A.norm();
cout<<"destance:"<<destance<<"\n";
}
这样就可以了

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