| 网站首页 | 业界新闻 | 小组 | 威客 | 人才 | 下载频道 | 博客 | 代码贴 | 在线编程 | 编程论坛
欢迎加入我们,一同切磋技术
用户名:   
 
密 码:  
共有 1003 人关注过本帖
标题:求助!有木有哪位大神帮我看看哪里出错了,万分感谢!
只看楼主 加入收藏
cpyxc
Rank: 1
等 级:新手上路
帖 子:12
专家分:0
注 册:2018-4-30
结帖率:0
收藏
已结贴  问题点数:10 回复次数:1 
求助!有木有哪位大神帮我看看哪里出错了,万分感谢!
代码如下:ps.//后为个人注释,方便阅读
#include <iostream>
#include<fstream>
#include <ctime>
#include <cmath>
#include <stdlib.h>
#include<stdio.h> //时间 //文件
#include <string>
#define random(x)(rand()%x)
using namespace std;
void thunder(int Dif,int Row,int Column,char *USer)
{
    int r,c,alls[22][22],backstage[22][22]={0};
    srand((int)time(0));
    for(r=1;r<=Row;r++)                                      // 生成alls(0~1)1是雷
    {
        for(c=1;c<=Column;c++)
        {
            if(random(6)<1)  {alls[r][c]=1;} else{alls[r][c]=0;};
        }
    };
    for(r=0;r<=Row+1;r++)                                //生成 backstage(正确答案)
    {
        for(int c=0;c<=Column+1;c++)
        {
            if(alls[r][c]==1)  
            {
                (int)backstage[r][c]='*';             //将1变为 *  代表雷
            }
            else
            {
                for(int i=r-1;i<=r+1;i++)             //将0变为数字 (代表周围雷数)
                    for(int j=c-1;j<=c+1;j++)
                    {
                        
                        if(alls[i][j]!=alls[r][c]&&alls[i][j]==1){backstage[r][c]++;};
                    }
            };  //else 结束
        };    // for 结束
    };          // for 结束
    cout<<"======================*********================================"<<endl;
    char surface[22][22];              //生成surface(用户界面)
    for(r=0;r<22;r++)                  //全部为零
        for(c=0;c<22;c++)
        {
            surface[r][c]='0';
        }
    for(r=1;r<=Row;r++)                 //中间化 #   形成0包围#的形式  (通过数  #-->(*||数字) 的个数  赢的时候停止循环)
        for(c=1;c<=Column;c++)
        {
            surface[r][c]='#';
        }
    for(r=1;r<=Row;r++)                      //输出  surface   界面  便于检查
    {
        for(c=1;c<=Column;c++) {cout<<"  "<<surface[r][c];};
        cout<<endl;
    };
    cout<<"请按格式输入"<<endl
        <<"前两个数字为坐标,最后一个数字“1”表示此位置为雷,“0”则表示不是。"<<endl
        <<"如:1 3 1  表示一行三列是雷;2 4 0 表示二行四列不是雷"<<endl
        <<"提示:当数字周围雷都被扫出时,可再次按要求输入此位置,可得到周围数字。"<<endl;
    long  i=10000000L;         //计算时间开始
    clock_t start,finish;
    double duration;
    start=clock();            
    while(i--);                //计算时间开始
    int num=Row*Column;        //计算#号个数
    while(num!=0)              //控制 是否点完所有位置
    {
        int x,y,judge;
       cin>>x>>y>>judge;
       if(alls[x][y]!=judge)
        {
            cout<<"you lose!!!"<<endl;
            cout<<"The answer is:"<<endl;
            for(r=1;r<=Row;r++)                    //输了   输出backstage  显示正确答案
                {
                  for(int c=1;c<=Column;c++)
                  {
                     cout<<"  "<<(char)(backstage[r][c]==42?backstage[r][c]:backstage[r][c]+'0');  //输出backstage
                  }
                  cout<<endl;
                }
            break;
        }
       else                                      
        {
            if(alls[x][y]==1)  {if(surface[x][y]=='#'){num--;}surface[x][y]='@'; }      // 雷 判断正确 显示“@”;数“#”
            else
            {
                if(backstage[x][y]!=0)                                                  //  数字 判断正确 显示数字
                {
                    if(surface[x][y]=='#'){num--; surface[x][y]=backstage[x][y]+'0'; }  //   数“#”
                   else
                    {
                        int lei_num=0;
                       for(int i=x-1;i<=x+1;i++)                                         //数 数字周围 雷的个数                                    
                            for(int j=y-1;j<=y+1;j++)
                            {
                                if(surface[i][j]=='@')
                               lei_num++;
                            }
                       if(backstage[x][y]==lei_num)                                   // 看数字周围雷是否全部扫出  提示 显示数字周围
                        {
                            for(int i=x-1;i<=x+1;i++)
                                for(int j=y-1;j<=y+1;j++)
                                        if(surface[i][j]=='#')                         //数“#”
                                        {
                                            surface[i][j]=backstage[i][j]+'0';
                                            num--;   
                                        }
                        }
                    }
                }
                else                                                                   // 数字为零时   显示零周围的零
                {
                    if(surface[x][y]=='#'){num--;};                                    //数“#”
                   surface[x][y]=backstage[x][y]+'0';
                    for(int i=x-1;i<=x+1;i++)                                          //  显示零周围的数字
                        for(int j=y-1;j<=y+1;j++)
                            if(surface[i][j]=='#')                                     // 避免 死循环
                            {
                                surface[i][j]=backstage[i][j]+'0';               
                                num--;                                                 //数“#”
                            }
                            for(int k=0;k<20;k++)                                       //最多20层零 (点出最边上的零)
                            {
                                for (int R=1;R<=Row;R++)                                //检查所有零
                                    for(int C=1;C<=Column;C++)                          //再次显示零周围的数字
                                    {
                                        if(surface[R][C]=='0')
                                        {
                                            for(int i=R-1;i<=R+1;i++)
                                                for(int j=C-1;j<=C+1;j++)
                                                {
                                                    if(surface[i][j]=='#')                         // 避免 死循环 数“#”
                                                    {
                                                        surface[i][j]=backstage[i][j]+'0';
                                                        num--;
                                                    }  
                                                }
                                        }
                                    } //匹配for 内
                            } //匹配 for 外
                }//匹配else
            }//匹配else
        }//匹配els
        cout<<endl;
        cout<<"======================*********================================"<<endl;
        for(r=1;r<=Row;r++)                                                                          //输出界面(已修改)
        {
            for(c=1;c<=Column;c++) {cout<<"  "<<surface[r][c];};
            cout<<endl;
        };
    }                                                                                               //匹配while
    finish=clock();                                                                                //计算时间结束
    duration=(double)(finish-start)/CLOCKS_PER_SEC;                                                //时间变量
    if(num==0)                                                                                      //所有
    {
        cout<<"              You win!  Congratulations!!                 "<<endl;
        cout<<"                Your time is: "<<duration<<endl;
        if(Dif==1)                                                                            //读取 简单扫雷 的存储文件
        {
            string Name;
           string name[6];
           double Time,rang;
           double times[6];
           int i=0;
           ifstream inf("扫雷 简单.txt");
           for(i=0;i<5;i++)                                                                    //文件中信息导入到数组里
            {
                inf>>Name;inf>>rang>>Time;
               name[i]=Name;
               times[i]=Time;
            }
            inf.close();
            name[5]=USer;                                                                   //本轮玩家信息
            times[5]=duration;
           double t1=0;
           string t2;
            for(int j=0;j<5;j++)                                                               //冒泡排序法
            {                    
                for(i=0;i<5-j;i++)
                {
                    if(times[i]>times[i+1])
                    {
                        t1=times[i];
                       times[i]=times[i+1];
                       times[i+1]=t1;
                       t2=name[i];
                       name[i]=name[i+1];
                       name[i+1]=t2;
                    }
                }
            }
            ofstream outf("扫雷 简单.txt");
           for(i=0;i<5;i++)                                                                   //将前五名玩家信息存储到文件中
            {
                cout<<name[i]<<"    "<<i+1<<"   "<<times[i]<<endl;
               outf<<name[i]<<"    "<<i+1<<"   "<<times[i]<<endl;
            }
           outf.close();
        }
        if(Dif==2)                                                                            //读取 一般扫雷 的存储文件
        {
            string Name;
           string name[6];
           double Time,rang;
           double times[6];
           int i=0;
           ifstream inf("扫雷 一般.txt");
           for(i=0;i<5;i++)                                                                    //文件中信息导入到数组里
            {
                inf>>Name;inf>>rang>>Time;
               name[i]=Name;
               times[i]=Time;
            }
            inf.close();
            name[5]=USer;                                                                   //本轮玩家信息
            times[5]=duration;
           double t1=0;
           string t2;
            for(int j=0;j<5;j++)                                                               //冒泡排序法
            {                    
                for(i=0;i<5-j;i++)
                {
                    if(times[i]>times[i+1])
                    {
                        t1=times[i];
                       times[i]=times[i+1];
                       times[i+1]=t1;
                       t2=name[i];
                       name[i]=name[i+1];
                       name[i+1]=t2;
                    }
                }
            }
            ofstream outf("扫雷 一般.txt");
           for(i=0;i<5;i++)                                                                   //将前五名玩家信息存储到文件中 并输出
            {
                cout<<name[i]<<"    "<<i+1<<"   "<<times[i]<<endl;
               outf<<name[i]<<"    "<<i+1<<"   "<<times[i]<<endl;
            }
           outf.close();
        }
        if(Dif==3)                                                                            //读取 困难扫雷 的存储文件
        {
            string Name;
           string name[6];
           double Time,rang;
           double times[6];
           int i=0;
           ifstream inf("扫雷 困难.txt");
           for(i=0;i<5;i++)                                                                    //文件中信息导入到数组里
            {
                inf>>Name;inf>>rang>>Time;
               name[i]=Name;
               times[i]=Time;
            }
            inf.close();
            name[5]=USer;                                                                   //本轮玩家信息
            times[5]=duration;
           double t1=0;
           string t2;
            for(int j=0;j<5;j++)                                                               //冒泡排序法
            {                    
                for(i=0;i<5-j;i++)
                {
                    if(times[i]>times[i+1])
                    {
                        t1=times[i];
                       times[i]=times[i+1];
                       times[i+1]=t1;
                       t2=name[i];
                       name[i]=name[i+1];
                       name[i+1]=t2;
                    }
                }
            }
            ofstream outf("扫雷 困难.txt");
           for(i=0;i<5;i++)                                                                   //将前五名玩家信息存储到文件中
            {
                cout<<name[i]<<"    "<<i+1<<"   "<<times[i]<<endl;
               outf<<name[i]<<"    "<<i+1<<"   "<<times[i]<<endl;
            }
           outf.close();
        }
    }
}
void scale(int dif,char *User)    //选择难度
{
    int row,column;
    if(dif==1) {row=3;column=3;}
    if(dif==2) {row=7;column=7;}
    if(dif==3)  {row=10;column=10;}
    cout<<"The scale is: "<<row<<"*"<<column<<endl;
    thunder(dif,row,column,User);
};
int main()
{   
    int Continue=1;
    int difficulty;
    char user[10];
    cout<<"                       Welcom to the game!                  "<<endl
        <<"                         请输入用户名!                      "<<endl;
    cin>>user;
    while(Continue==1)
    {
       cout<<"=======================*******************======================="<<endl
           <<"                          请选择难度!                        "<<endl
           <<"                          简单——1                           "<<endl
           <<"                          一般——2                           "<<endl
           <<"                          困难——3                           "<<endl;
       cin>>difficulty;
       scale(difficulty,user);
        cout<<"继续游戏——1     结束游戏——0"<<endl;
        cin>>Continue;
    }
    return 0;
}
搜索更多相关主题的帖子: Name int for cout times 
2018-04-30 14:38
Jonny0201
Rank: 11Rank: 11Rank: 11Rank: 11
等 级:贵宾
威 望:52
帖 子:488
专家分:2603
注 册:2016-11-7
收藏
得分:10 
(int)backstage[r][c]='*';
这种你是从哪里看到这么写的?
backstage[r][c]=(int)'*';
2018-05-01 10:46
快速回复:求助!有木有哪位大神帮我看看哪里出错了,万分感谢!
数据加载中...
 
   



关于我们 | 广告合作 | 编程中国 | 清除Cookies | TOP | 手机版

编程中国 版权所有,并保留所有权利。
Powered by Discuz, Processed in 0.023461 second(s), 9 queries.
Copyright©2004-2024, BCCN.NET, All Rights Reserved