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问题点数：0  回复次数：8

1. arrA[a,b,c,d,e,f] = arrB[n];
2. 要求a<b<c<d<e<f<33;

arrA[ 0, 1, 2, 3, 4, 5] = arrB[0]
arrA[ 0, 1, 2, 3, 4, 6] = arrB[1]
arrA[ 0, 1, 2, 3, 4,32] = arrB[27]
arrA[ 0, 1, 2, 3, 5, 6] = arrB[28]
arrA[ 0, 1, 2, 3, 5, 7] = arrB[29]
arrA[ 0, 1, 2, 3, 5,32] = arrB[54]
arrA[ 0, 1, 2, 3, 6, 7] = arrB[55]
arrA[ 0, 1, 2, 4, 5, 6] = arrB[406]
arrA[ 0, 1, 2, 6, 7, 8] = arrB[1135]
arrA[ 0, 1, 2, 7, 8, 9] = arrB[1460]
arrA[ 0, 1, 3, 4, 5, 6] = arrB[4060]
arrA[ 0, 1, 3, 4, 5, 7] = arrB[5138]
arrA[ 0, 1, 4, 5, 6, 7] = arrB[7144]

2. arrB[N] = arrA[a,b,c,d,e,f]中的abcdef表达式或者程序
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DO IT YOURSELF !
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arrA[ 0, 1, 2, 3, 4, 5] = arrB[0]--->arrA[0*32^5+1*32^4+2*32^3+3*32^2+4*32^1+5*32^0-0*32^5+1*32^4+2*32^3+3*32^2+4*32^1+5*32^0]
arrA[ 0, 1, 2, 3, 4, 6] = arrB[1]--->arrA[0*32^5+1*32^4+2*32^3+3*32^2+4*32^1+6*32^0-0*32^5+1*32^4+2*32^3+3*32^2+4*32^1+5*32^0]
...
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