#include"stdio.h"
int sum(int *p,int z)
{ int i,s=0;
 for(i=0;i<=z;i++,p++)
              {s+=*p;}
              return s;}
int main(){
    int a[10]={1,2,3,4,5,6,7,8,9,10    };
    int *x,m,n,z;
    printf("input n and m like n m:\n");
    scanf("%d %d",&n,&m);
    x=a+n-1;
    z=m-n;
    printf("the sum is:",sum(x,z));
   
}

咋输出什么都没呢？求问题出在哪里？？？

我来做眼科大夫了

#include"stdio.h"

int sum(int *p,int z)

{ int i,s=0;

for(i=0;i<=z;i++,p++)

              {s+=*p;}

              return s;}

int main(){

    int a[10]={1,2,3,4,5,6,7,8,9,10    };

    int *x,m,n,z;

    printf("input n and m like n m:\n");

    scanf("%d %d",&n,&m);

    x=a+n-1;

    z=m-n;

    printf("the sum is:%d",sum(x,z)); //  printf("the sum is:",sum(x,z));......

  



}

的确。。。printf("the sum is:%d",sum(x,z));   少加了个%d

#include <stdio.h>

int sum(int *p,int z);

int main()
{
    int a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    int *x, m, n, z;

    printf("input n and m like n m:\n");
    scanf("%d %d", &n, &m);
    x = a + n - 1;
    z = m - n;
    printf("the sum is:%d\n", sum(x, z)); //楼主程序是对的，只是这行少了 %d，楼主的代码风格也需要改善
}
int sum(int *p,int z)
{
    int i, s = 0;
    for (i = 0; i <= z; i++, p++)
    {
        s += *p;
        printf("%d %d\n", i, s);
    }
    return s;
}

噢。是这么回事。谢谢楼上三位，呵呵