题目设计要求：将1、2、3、4、5和6填入下表中，要使每一列右边的数字比左边的数字大，每一行下边的数字比上边的数字大。按此要求，有几种填写方法，表格形式
***
***   3X2的表格
#include <stdio.h>
int main()
{

 
    int i,j,k,h,s,b;
    int a[6];
    a[0]=1;
    a[5]=6;
      for(i=5;i>2;i--)
      {
          a[4]=i;
             for(j=5;j>2;j--)
             {
                a[3]=j;
                 for(k=5;k>2;k--)
                 {   a[2]=k;
                     for(h=5;h>2;h--)
                     {
                         a[1]=h;
                        if(a[5]>a[4]&&a[4]>a[3]&&a[2]>a[1]&&a[1]>a[0]&&a[5]>a[2]&&a[4]>a[1]&&a[3]>a[0])
                        {
                            int z=0;
                            for(s=0;s<5;s++)
                            {  
                              
                              for(b=s+1;b<5;b++)
                              {
                                    
                                    if(a[s]==a[b])
                                    
                                        z++;
                                    
                                    
        
                              }
                               if(z==0)
                                printf("%d,%d,%d\n%d,%d,%d\n",a[0],a[1],a[2],a[3],a[4],a[5]);
      
                            }
                        }
     
                     }
                 }

             }
      }
 return 0;
}

各位大侠帮忙啊  老师凶死了 还说什么输出界面要友好 我了个去 我一年没碰C了  大一学的就不好

个人表示写不出来哎！老了！

#include <stdio.h>
#include<stdlib.h>
int main()
{


    int i,j,k,h,s,b;
    int a[6];
    a[0]=1;
    a[5]=6;
      for(i=5;i>2;i--)
      {
          a[4]=i;
             for(j=5;j>2;j--)
             {
                a[3]=j;
                 for(k=5;k>2;k--)
                 {   a[2]=k;
                     for(h=5;h>2;h--)
                     {
                         a[1]=h;
                        if(a[5]>a[4]&&a[4]>a[3]&&a[2]>a[1]&&a[1]>a[0]&&a[5]>a[2]&&a[4]>a[1]&&a[3]>a[0])
                        {
                            int z=0;
                            for(s=0;s<5;s++)
                            {  
                              
                              for(b=s+1;b<5;b++)
                              {
                                    
                                    if(a[s]==a[b])
                                    
                                        z++;
                                    
                                    
        
                              }
                               if(z==0)
                                printf("%d,%d,%d\n%d,%d,%d\n",a[0],a[1],a[2],a[3],a[4],a[5]);
                               system("pause");
      
                            }
                        }
     
                     }
                 }

             }
      }
return 0;
}




我运行了一遍，行啊。。。

这个程序通用性不好，你用循环做，选择排序或者冒泡排序，网上找找