我想写一个存储图片的程序段，编译显示的信息是：error C2664: 'image_write' : cannot convert parameter 2 from 'struct _iobuf *' to 'char *'
        Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast

出错的地方我用红字标出来了，等待高手指点哈


我的代码如下：
#include <stdio.h>
#include<stdlib.h>
#define X_SIZE  128      /*图像的横宽    */
#define Y_SIZE  128      /*图像的纵长    */
#define X_EXP    7         /* X_EXP=log2(X_SIZE)       */
#define Y_EXP    7         /*Y_EXP=log2(X_SIZE)        */
#define HIGH      255      /*2值图像的高端值             */
#define LOW       0        /*2值图像的低端值              */


int image_read(unsigned char image[Y_SIZE][X_SIZE], char *filename);
int image_write(unsigned char image[Y_SIZE][X_SIZE], char *filename);
        
int main ( )
        {
            FILE * fp=NULL;  //先命名指针和定义数组

            unsigned char image[Y_SIZE][X_SIZE]={{1,1,0,1},{0,0,1,0},{1,0,1}};
            
        
            if((fp=fopen("c:\\test0.bmp","wb"))==NULL){
            printf("write the bmp file has failed\n");
            return 1;
            }
                  
            


 image_write(image, fp);
            
            }



int image_write(unsigned char image[128][128], char *filename)
{
    FILE   *fp;
    fp = fopen ("test0.bmp", "wb");
    if (fp == NULL) return -1;
    else {
        fwrite(image, (size_t)X_SIZE, (size_t)Y_SIZE, fp);
        fclose(fp);
        return 0;
        }
    }        

在线等，高手快出手啊

函数声明里，第二个参数是char*，但是你在调用的时候传人的参数是FILE*

#include <stdio.h>
#include<stdlib.h>
#define X_SIZE  128      /*图像的横宽    */
#define Y_SIZE  128      /*图像的纵长    */
#define X_EXP    7         /* X_EXP=log2(X_SIZE)       */
#define Y_EXP    7         /*Y_EXP=log2(X_SIZE)        */
#define HIGH      255      /*2值图像的高端值             */
#define LOW       0        /*2值图像的低端值              */


int image_read(unsigned char image[Y_SIZE][X_SIZE], char *filename);
int image_write(unsigned char image[Y_SIZE][X_SIZE], /*char *filename*/FILE* fp);
        
int main ( )
{
            FILE * fp=NULL;  //先命名指针和定义数组

            unsigned char image[Y_SIZE][X_SIZE]={{1,1,0,1},{0,0,1,0},{1,0,1}};
            
        
            if((fp=fopen("c:\\test0.bmp","wb"))==NULL){
            printf("write the bmp file has failed\n");
            return 1;
            }
            
            
            
            
            image_write(image, fp);

            return 0;
            
}



int image_write(unsigned char image[128][128], /*char *filename*/FILE* fp)
{
    //FILE   *fp;
    if (NULL == fp)
        return -1;

    fp = fopen ("test0.bmp", "wb");
    if (fp == NULL) return -1;
    else {
        fwrite(image, (size_t)X_SIZE, (size_t)Y_SIZE, fp);
        fclose(fp);
        return 0;
    }
}

收到的鲜花

• madrabbit 于 2010-07-24 21:08 送鲜花  3朵   附言：我很赞同

另外一种方法是在主函数里不要读文件，而是传入文件名。

 image_write(image, "c:\\test0.bmp");

是的，传入文件名就可以了

恩，问题真的如你所说的。非常感谢!