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标题:求C语言编写五子棋指导
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无为无执
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求C语言编写五子棋指导
五子棋系统
要求:双人对下、人-机对下,系统自动判别输赢。
哪位有指导传一个,邮箱czq870516@163.com,小弟感激不尽!
搜索更多相关主题的帖子: C语言 五子棋 编写 指导 
2007-03-27 21:43
neverTheSame
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在百度里找一下就有很多.

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2007-03-28 11:06
木子雨彐
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# include<stdio.h>

# include<stdio.h>

# include<stdio.h>

# include<stdio.h>//插入输入输出头文件

# include<string.h>//字符数组的函数定义的头文件

# include<stdlib.h>//stdlib 头文件即standard library标准库头文件stdlib 头文件里包含了C、C++语言的最常用的系统函数该 ,文件包含了C语言标准库函数的定义.

# define SPA 0//在C或C++语言源程序中允许用一个标识符来表示一个字符串。 “define”为宏定义命令。

# define MAN 1

# define COM 2

    /* 空位置设为0 ,玩家下的位置设为1 ,电脑下的位置设为2 */

#define ORDEX 15

int qipan[ORDEX][ORDEX];  //自己定义的预处理函数,以二维数组形式构建棋盘  /* 15*15的棋盘 */



typedef struct//typedef的作用是在C中定义一个结构体类型

{

    int iFlag;

    int iX, iY;

}ScmPiece;

int g_iPieceLen;

ScmPiece g_ScmGame1, g_ScmGame2;





void start();  /* 程序的主要控制函数 */

void draw();   /* 画棋盘 */

int Victory( ScmPiece * pScmPiece );  /* 判断胜利 p q为判断点坐标 */

void AI(int *p,int *q);     /* 电脑下子 p q返回下子坐标 */

int value(int p,int q);     /* 计算空点p q的价值 */

int qixing(int n,int p,int q);    /* 返回空点p q在n方向上的棋型 n为1-8方向 从右顺时针开始数 */

void yiwei(int n,int *i,int *j);   /* 在n方向上对坐标 i j 移位 n为1-8方向 从右顺时针开始数  */



void InitGame()
{

    int i;

    g_iPieceLen = ORDEX * ORDEX;

    g_ScmGame1.iX = 0;

    g_ScmGame1.iY = 0;

    g_ScmGame1.iFlag = COM;

    g_ScmGame2.iX = 7;

    g_ScmGame2.iY = 7;

    g_ScmGame2.iFlag = MAN;

    for( i=0; i < ORDEX*ORDEX; ++i )

        *( (int*)qipan + i ) = SPA;

}



void main()//主函数

{

    char k;

    do{

        InitGame();

        start();

        printf("\t\t\t还要再来一把吗?输入y或n:"); getchar(); scanf("%c",&k);

        while(k!='y'&&k!='n')
        {
            printf("\t\t\t输入错误,请重新输入\n");
        scanf("%c",&k);
        }

        system("cls");//清屏

    }
    while(k=='y');

    printf("\t\t\t谢谢使用!\n");

}

void MakePiece( ScmPiece * pScmPiece, int iGameFlag )
{

    if( iGameFlag )

    {

        printf("\t\t\t请下子:");

        while( scanf( "%d%d", &pScmPiece->iX, &pScmPiece->iY ) )

        {

            if( ( pScmPiece->iX < 0 || pScmPiece->iX > ORDEX-1 ) || ( pScmPiece->iY < 0 || pScmPiece->iY > ORDEX-1 ) )

                printf( "\t\t\t坐标错误!请重新输入:");

            else if( qipan[pScmPiece->iX][pScmPiece->iY] )

                printf( "\t\t\t该位置已有子!请重新输入:");

            else break;

        }

    }

    qipan[pScmPiece->iX][pScmPiece->iY] = pScmPiece->iFlag;

    --g_iPieceLen;

    system("cls");//清屏

    draw();

    if( iGameFlag == 0 )

        printf("\t\t\t电脑下在%d %d\n", pScmPiece->iX, pScmPiece->iY );

}

void start()

{

    int choice;

    //ScmPiece ScmGameTemp1, ScmGameTemp2;/* a1 b1储存玩家上手坐标 c1 d1储存电脑上手坐标 */

    printf("\t╔═══════════════════════════════╗\n");

    printf("\t║                                                              ║\n");

    printf("\t║      欢迎使用五子棋对战程序     祝您玩的愉快挑战无极限       ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║                 ___________________________                  ║\n");

    printf("\t║                 _____________________                   ║\n");

    printf("\t║                │ │                   │ │                 ║\n");

    printf("\t║                │ │                   │ │                 ║\n");

    printf("\t║                │ │     五 子 棋      │ │                 ║\n");

    printf("\t║                │ │                   │ │                 ║\n");

    printf("\t║                │ │___________________│ │                 ║\n");

    printf("\t║                │_________________________│                 ║\n");

    printf("\t║                      ._[__________]_.                        ║\n");

    printf("\t║                  .___|_______________|___.                   ║\n");

    printf("\t║                   |::: ____             |                    ║\n");

    printf("\t║                   |    ~~~~ [READY GO]  |                    ║\n");

    printf("\t║                   |_____________________|                    ║\n");
 
    printf("\t║                                                              ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║              直 二 斜 黑 白 星 松 雨 花 寒                   ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║              指 十 月 玉 莲 月 丘 月 残 星                ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║              游 六 明 银 垂 长 新 金 二 溪                ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║              星 局 月 月 俏 峡 宵 星 月 月                ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║              斜 先 堪 倚 云 恒 瑞 追 并 疏                ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║              慧 弃 称 明 浦 水 山 黑 白 星                ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║              星 二 朋 星 岚 流 腥 玉 莲 首                   ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║                , 。 , 。 , 。 , 。 ,                  ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║                                                              ║\n");

    printf("\t║           1.人机对战                 2.人人对战              ║\n");

    printf("\t║                                                              ║\n");

    printf("\t╚═══════════════════════════════╝\n");

    printf("\t\t\t\t请输入  1    2  :");

    while( scanf( "%d", &choice ), choice!=1 && choice!=2 )

        printf( "\t\t\t输入错误,请重新输入:" );

    system("cls");

    if( choice == 1 )

    {                                    /* 人机模式 */

        printf("\t\t\t欢迎使用五子棋人机对战!\n\t\t下子请输入坐标(如13 6)中间以空格分隔。\n\n\n");

        draw();

        printf("\t\t\t先下请按1,后下请按2:");

        while( scanf( "%d", &choice ), choice!=1 && choice!=2 )

            printf( "\t\t\t输入错误,请重新输入:" );

        if( choice == 2 )

            MakePiece( &g_ScmGame2, 0 );

        choice = 1;

    }

    else

    {

        printf("\t\t欢迎使用五子棋人人对战!下子请输入坐标(如13 6)。\n\n\n");

        draw();

    }

    while( g_iPieceLen )

    {

        MakePiece( &g_ScmGame1, 1 );

        if( Victory( &g_ScmGame1 ) )

        {
            printf("\t\t\t哈哈哈!我把电脑都打败了!\n");

            printf("\t\t\t电脑神马的都是浮云!!!\n");

            return;

        }    /* 玩家赢 */

        if( choice == 1 )

        {

            AI( &g_ScmGame2.iY, &g_ScmGame2.iX );

            MakePiece( &g_ScmGame2, 0 );

            if( Victory( &g_ScmGame2 ) )

            {               /* 电脑赢 */

                int iChoice;
                printf("\t\t\t你输了哦!\n");

                printf("\t\t\t要悔棋吗?请输入y或n:");

STARTFLAGE:

                setbuf( stdin, NULL );

                scanf( "%c", &iChoice );

                switch( (char)iChoice ){

                case 'y':

                case 'Y':

                    g_iPieceLen += 2;

                    qipan[g_ScmGame2.iX][g_ScmGame2.iY] = SPA;

                    qipan[g_ScmGame1.iX][g_ScmGame1.iY] = SPA;

                    system("cls"); draw();

                    break;

                case 'n':

                case 'N':

                    printf( "\t\t\t下不过电脑很正常,请不要灰心!!!\n" );

                    return;

                default:

                    printf("\t\t\t输入错误,请重新输入:");

                    goto STARTFLAGE;

                }

            }

        }

        else

        {

            MakePiece( &g_ScmGame2, 1 );

            if( Victory( &g_ScmGame2 ) )

            {
                printf("\t\t\t哈哈哈!我把电脑都打败了!\n");
                printf("\t\t\t电脑神马的都是浮云!!!\n");

                return;

            }

        }

    }

    printf("\t\t\t和局\n");

}

void draw() /* 画棋盘 */

{

    int i,j;

    char p[15][15][4];

    for(j=0;j<15;j++)

        for(i=0;i<15;i++){

            if(qipan[j][i]==SPA) strcpy(p[j][i],"  \0");

            if(qipan[j][i]==MAN) strcpy(p[j][i],"●\0");

            if(qipan[j][i]==COM) strcpy(p[j][i],"◎\0");

        }

    printf("         0   1   2   3   4   5   6   7   8   9   10  11  12  13  14  \n");

    printf("       ┌─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┬─┐\n");

    for(i=0,j=0;i<14;i++,j++){

    printf("     %2d│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%d\n",j,p[i][0],p[i][1],p[i][2],p[i][3],p[i][4],p[i][5],p[i][6],p[i][7],p[i][8],p[i][9],p[i][10],p[i][11],p[i][12],p[i][13],p[i][14],j);

    printf("       ├─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┼─┤\n");

    }

    printf("     14│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│%s│0\n",p[14][0],p[14][1],p[14][2],p[14][3],p[14][4],p[14][5],p[14][6],p[14][7],p[14][8],p[14][9],p[14][10],p[14][11],p[14][12],p[14][13],p[14][14]);

    printf("       └─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┴─┘\n");

    printf("         0   1   2   3   4   5   6   7   8   9   10  11  12  13  14  \n");

}

static int DirectionValue( int * piX, int * piY, int iDirection )
{

    switch( iDirection )
    {

    case 0:

        --*piX;

        break;

    case 4:

        ++*piX;

        break;

    case 1:

        --*piY;

        break;

    case 5:

        ++*piY;

        break;

    case 2:

        --*piX; --*piY;

        break;

    case 6:

        ++*piX; ++*piY;

        break;

    case 3:

        --*piX; ++*piY;

        break;

    case 7:

         ++*piX; --*piY;

        break;

    }

    if( (*piX >= 0 && *piX <= ORDEX-1) && (*piY >= 0 && *piY <= ORDEX-1) )

        return 1;

    else return 0;

}

static int SubVictory( ScmPiece * pScmPiece, int iDirection )
{

    int iX = pScmPiece->iX;

    int iY = pScmPiece->iY;

    int iPieceCount = 1;

    while( DirectionValue( &iX, &iY, iDirection ) && qipan[iX][iY] ==  pScmPiece->iFlag )

        ++iPieceCount;

    iX = pScmPiece->iX;

    iY = pScmPiece->iY;

    while( DirectionValue( &iX, &iY, iDirection+4 ) && qipan[iX][iY] ==  pScmPiece->iFlag )

        ++iPieceCount;

    return iPieceCount;

}

int Victory( ScmPiece * pScmPiece )      /* 判断胜利 p q为判断点坐标,胜利返回1,否则返回0 */

{

    int iDirection = 0;

    while( iDirection < 4 )

        if( SubVictory( pScmPiece, iDirection++ ) >= 5 )

            return 1;

    return 0;

}

void AI(int *p,int *q)           /* 电脑下子 *p *q返回下子坐标 */

{

    int i,j,k,max=0,I,J;        /* I J为下点坐标 */

    for(j=0;j<15;j++)

        for(i=0;i<15;i++)

            if(qipan[j][i]==SPA)
            {      /* 历遍棋盘,遇到空点则计算价值,取最大价值点下子。 */

                k=value(i,j);

                if(k>=max)
                {
                    I=i;
                    J=j;
                    max=k;
                }

            }

    *p=I;
    *q=J;

}

int value(int p,int q) /* 计算空点p q的价值 以k返回 */

{

    int n=1,k=0,k1,k2,K1,K2,X1,X2,Y1,Y2,Z1,Z2,temp;  

    int a[2][4][4]={40,400,3000,10000,6,10,600,10000,20,120,200,0,6,10,500,0,30,300,2500,5000,2,8,300,8000,26,160,0,0,4,20,300,0};

           /* 数组a中储存己方和对方共32种棋型的值  己方0对方1    活0冲1空活2空冲3    子数0-3(0表示1个子,3表示4个子) */

    while(n!=5)
    {

        k1=qixing(n,p,q); n+=4;            /* k1,k2为2个反方向的棋型编号 */

        k2=qixing(n,p,q); n-=3;

        if(k1>k2)
        {
            temp=k1; k1=k2; k2=temp;
        }  /* 使编号小的为k1,大的为k2 */

        K1=k1; K2=k2;       /* K1 K2储存k1 k2的编号 */

        Z1=k1%10; Z2=k2%10; k1/=10; k2/=10; Y1=k1%10; Y2=k2%10; k1/=10; k2/=10; X1=k1%10; X2=k2%10;

            /* X Y Z分别表示 己方0对方1    活0冲1空活2空冲3    子数0-3(0表示1个子,3表示4个子) */

        if(K1==-1)
        {
            if(K2<0)
            {
                k+=0; continue;
            }
            else
                k+=a[X2][Y2][Z2]+5; continue;
        };    /* 空棋型and其他 */

        if(K1==-2)
        {
            if(K2<0)
            {
                k+=0; continue;
            }
            else
                k+=a[X2][Y2][Z2]/2; continue;
        };       /* 边界冲棋型and其他 */

        if(K1==-3)
        {
            if(K2<0)
            {
                k+=0; continue;
            }
            else
                k+=a[X2][Y2][Z2]/3; continue;
        };    /* 边界空冲棋型and其他 */

        if(((K1>-1&&K1<4)&&((K2>-1&&K2<4)||(K2>9&&K2<14)))||((K1>99&&K1<104)&&((K2>99&&K2<104)||(K2>109&&K2<114))))
        {

            /* 己活己活 己活己冲 对活对活 对活对冲 的棋型赋值*/

            if(Z1+Z2>=2)
            {
                k+=a[X2][Y2][3]; continue;
            }

            else
            {
                k+=a[X2][Y2][Z1+Z2+1]; continue;
            }

        }

        if(((K1>9&&K1<14)&&(K2>9&&K2<14))||((K1>109&&K1<114)&&(K2>109&&K2<114)))
        {

            /* 己冲己冲 对冲对冲 的棋型赋值*/

            if(Z1+Z2>=2)
            {
                k+=10000;
                continue;
            }

            else
            {
                k+=0;
                continue;
            }

        }

       /*if(((K1>-1&&K1<4)&&((K2>99&&K2<104)||(K2>109&&K2<114)))||((K1>9&&K1<14)&&((K2>99&&K2<104)||(K2>109&&K2<1 14))))
        {

              己活对活 己活对冲 己冲对活 己冲对冲 的棋型赋值*/

           /*if(Z1==3||Z2==3)
            {
                k+=10000;
                continue;
            }

            else
            {
                k+=a[X2][Y2][Z2]+a[X1][Y1][Z1]/4;
                continue;
            }

        } */

        else
        {
            k+=a[X1][Y1][Z1]+a[X2][Y2][Z2];
            continue;  
        }    /* 其他棋型的赋值 */

    }

    return k;

}

int qixing(int n,int p,int q)            /* 返回空点p q在n方向上的棋型号 n为1-8方向 从右顺时针开始数 */

{

    int k,m=0;  /* 棋型号注解:  己活000-003 己冲010-013 对活100-103 对冲110-113 己空活020-023 己空冲030-033 对空活120-123 对空冲130-133 空-1 边界冲-2 边界空冲-3*/

    yiwei(n,&p,&q);

    if(p<0||p>14||q<0||q>14) k=-2;                                      /* 边界冲棋型 */

    switch(qipan[q][p]){

        case COM:{

                    m++; yiwei(n,&p,&q);

                    if(p<0||p>14||q<0||q>14) { k=m+9; return k; }

                    while(qipan[q][p]==COM) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+9; return k; } }

                    if(qipan[q][p]==SPA) k=m-1;                         /* 己方活棋型 */

                     else k=m+9;                                         /* 己方冲棋型 */

                 }break;

        case MAN:{

                    m++; yiwei(n,&p,&q);

                    if(p<0||p>14||q<0||q>14) { k=m+109; return k; }

                    while(qipan[q][p]==MAN) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+109; return k; } }

                    if(qipan[q][p]==SPA) k=m+99;                         /* 对方活棋型 */

                    else k=m+109;                                        /* 对方冲棋型 */

                 }break;

        case SPA:{

                    yiwei(n,&p,&q);

                    if(p<0||p>14||q<0||q>14) { k=-3; return k; }         /* 边界空冲棋型 */

                    switch(qipan[q][p]){

                    case COM:{

                                m++; yiwei(n,&p,&q);

                                if(p<0||p>14||q<0||q>14) { k=m+29; return k; }

                                while(qipan[q][p]==COM) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+29; return k; } }

                                if(qipan[q][p]==SPA) k=m+19;                      /* 己方空活棋型 */

                                else k=m+29;                                      /* 己方空冲棋型 */

                             }break;

                    case MAN:{

                                m++; yiwei(n,&p,&q);

                                if(p<0||p>14||q<0||q>14) { k=m+129; return k; }

                                while(qipan[q][p]==MAN) { m++; yiwei(n,&p,&q); if(p<0||p>14||q<0||q>14) { k=m+129; return k; } }           

                                if(qipan[q][p]==SPA) k=m+119;                     /* 对方空活棋型 */

                                else k=m+129;                                     /* 对方空冲棋型 */

                             }break;

                    case SPA: k=-1; break;                                         /* 空棋型 */

                    }

                }break;

    }

    return k;

}

void yiwei(int n,int *i,int *j)        /* 在n方向上对坐标 i j 移位 n为1-8方向 从右顺时针开始数 */

{

    switch(n){

    case 1: *i+=1; break;

    case 2: *i+=1; *j+=1; break;

    case 3: *j+=1; break;

    case 4: *i-=1; *j+=1; break;

    case 5: *i-=1; break;

    case 6: *i-=1; *j-=1; break;

    case 7: *j-=1; break;

    case 8: *i+=1; *j-=1; break;

    }

}
2015-07-02 09:42
快速回复:求C语言编写五子棋指导
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