struct stu
{
int num;
char *name;
char sex;
float score;
}boy[5]={
{101,"Li ping",'M',45},
{102,"Zhang ping",'M',62.5},
{103,"He fang",'F',92.5},
{104,"Cheng ling",'F',87},
{105,"Wang ming",'M',58},
};
main()
{
int i,c=0;
float ave,s=0;
for(i=0;i<5;i++)
{
s+=boy[i].score;
if(boy[i].score<60) c+=1;
}
printf("s=%f\n",s);
ave=s/5;
printf("average=%f\ncount=%d\n",ave,c);
}
编译完TC20提示编译错误：Declaration syntax error (说明出现语法错误)
但是本人却找不到错在哪
帮帮我 ‘’‘’‘’‘’‘’‘’‘’‘’‘’‘’‘’‘’大虾们

struct stu
{
int num;
char *name;
char sex;
float score;
}boy[5]={
{101,"Li ping",'M',45},
{102,"Zhang ping",'M',62.5},
{103,"He fang",'F',92.5},
{104,"Cheng ling",'F',87},
{105,"Wang ming",'M',58},
};
main()
{
int i,c=0;
float ave,s=0;
for(i=0;i<5;i++)
{
s+=boy[i].score;
if(boy[i].score<60) c+=1;
}
printf("s=%f\n",s);
ave=s/5;
printf("average=%f\ncount=%d\n",ave,c);
getch();
}
我这里没有错误
s=345.00000
average=69.00000
count=2

程序没有错误
用编译器新建一次文件再编译试试

用Visual C++6.0编译器就没有问题,格式如下:
#include<stdio.h>
struct stu
{
int num;
char *name;
char sex;
float score;
}boy[5]={
{101,"Li ping",'M',45},
{102,"Zhang ping",'M',62.5},
{103,"He fang",'F',92.5},
{104,"Cheng ling",'F',87},
{105,"Wang ming",'M',58},
};
void main()
{
int i,c=0;
float ave,s=0;
for(i=0;i<5;i++)
{
s+=boy[i].score;
if(boy[i].score<60) c+=1;
}
printf("s=%f\n",s);
ave=s/5;
printf("average=%f\ncount=%d\n",ave,c);
}

如果有人需要VC++6.0编译器,可以发贴说明,我会发下载该编译器的网址,或者给我邮箱发信息我给你回复:chenjie3614@126.com

我也试过了,程序是没有错误的.