[求助]如何实现在线ＱＱ功能？
用asp如何实现在线ＱＱ的功能，从数据库里读取ＱＱ号，我自己弄了下从数据库读记录，只读出来了一条，这里有个循环，不知道该怎么写，把数据库里的记录都读出来．？
<%
Server.scriptTimeout="10"
connstr="DBQ="+server.mappath("\database\qq.mdb")+";DefaultDir=;DRIVER={Microsoft Access Driver (*.mdb)};"
set conn=Server.CreateObject("ADODB.connection")
conn.open connstr
set rs=server.CreateObject("adodb.recordset")
sql="select top 5 * from biao"
rs.open sql,conn,1,1
adm_qq=rs("qq")
QQ=split(adm_qq,",")
for N=0 to UBound(QQ)
MyQQ=MyQQ+QQ(N)+":"
next
%>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<link rel="stylesheet" href="lzimages/qq.css" type="text/css">
</head>
<script>
var online= new Array();
if (!document.layers)
document.write('<div id="divStayTopLeft" style="position:absolute">')
</script>
<layer id="divStayTopLeft">
<table border="0" width="110" cellspacing="0" cellpadding="0">
<tr><td width="110"><img src=lzimages/QQ_up.jpg width="118" height="69" border=0></td>
</tr>
<script src="http://webpresence.qq.com/getonline?Type=1&<%=Myqq%>"></script>
<% for N=0 to UBound(QQ) %>
<tr><td valign=middle background=lzimages/qq_middle.gif>
<script>
if (online[<%=n%>]==0)
document.write(" <img src=lzimages/QQoffline.gif border=0 align=middle><a class='qqb' target=blank href='http://wpa.qq.com/msgrd?V=1&Uin=<%=QQ(n)%>&Site=在线咨询&Menu=no' title='客服不在线，请留言'><%=QQ(n)%></a>");
else
document.write(" <img src=lzimages/QQonline.gif border=0 align=middle><a class='qqa' target=blank href='http://wpa.qq.com/msgrd?V=1&Uin=<%=QQ(n)%>&Site=在线咨询&Menu=no' title='在线即时交谈'><%=QQ(n)%></a>");
</script >
</td></tr>
<%next%>
<tr><td width="110"><img src=lzimages/QQ_down.jpg width="118" height="23" border=0></td>
</tr>
</table>
</layer>
<script type="text/javascript">
var verticalpos="frombottom"
if (!document.layers)
document.write('</div>')
function JSFX_FloatTopDiv()
{
//默认情况显示在屏幕左侧，若要显示在右侧，修改下面的
var startX =885,
startY =320;
var ns = (navigator.appName.indexOf("Netscape") != -1);
var d = document;
function ml(id)
{
var el=d.getElementById?d.getElementById(id):d.all?d.all[id]:d.layers[id];
if(d.layers)el.style=el;
el.sP=function(x,y){this.style.left=x;this.style.top=y;};
el.x = startX;
if (verticalpos=="fromtop")
el.y = startY;
else{
el.y = ns ? pageYOffset + innerHeight : document.body.scrollTop + document.body.clientHeight;
el.y -= startY;
}
return el;
}
window.stayTopLeft=function()
{
if (verticalpos=="fromtop"){
var pY = ns ? pageYOffset : document.body.scrollTop;
ftlObj.y += (pY + startY - ftlObj.y)/8;
}
else{
var pY = ns ? pageYOffset + innerHeight : document.body.scrollTop + document.body.clientHeight;
ftlObj.y += (pY - startY - ftlObj.y)/8;
}
ftlObj.sP(ftlObj.x, ftlObj.y);
setTimeout("stayTopLeft()", 10);
}
ftlObj = ml("divStayTopLeft");
stayTopLeft();
}
JSFX_FloatTopDiv();
</script>
</html>
