[求助]java中有没有取小数点后两位的函数？ - JAVA论坛

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[CODE]

// The 0 symbol shows a digit or 0 if no digit present
    NumberFormat formatter = new DecimalFormat("000000");
    String s = formatter.format(-1234.567);  // -001235
    // notice that the number was rounded up
    
    // The # symbol shows a digit or nothing if no digit present
    formatter = new DecimalFormat("##");
    s = formatter.format(-1234.567);         // -1235
    s = formatter.format(0);                 // 0
    formatter = new DecimalFormat("##00");
    s = formatter.format(0);                 // 00
    
    
    // The . symbol indicates the decimal point
    formatter = new DecimalFormat(".00");   // pay attention here, that is what you want
    s = formatter.format(-.567);             // -.57
    formatter = new DecimalFormat("0.00");
    s = formatter.format(-.567);             // -0.57
    formatter = new DecimalFormat("#.#");
    s = formatter.format(-1234.567);         // -1234.6
    formatter = new DecimalFormat("#.######");
    s = formatter.format(-1234.567);         // -1234.567
    formatter = new DecimalFormat(".######");
    s = formatter.format(-1234.567);         // -1234.567
    formatter = new DecimalFormat("#.000000");
    s = formatter.format(-1234.567);         // -1234.567000
    
    
    // The , symbol is used to group numbers
    formatter = new DecimalFormat("#,###,###");
    s = formatter.format(-1234.567);         // -1,235
    s = formatter.format(-1234567.890);      // -1,234,568
    
    // The ; symbol is used to specify an alternate pattern for negative values
    formatter = new DecimalFormat("#;(#)");
    s = formatter.format(-1234.567);         // (1235)
    
    // The ' symbol is used to quote literal symbols
    formatter = new DecimalFormat("'#'#");
    s = formatter.format(-1234.567);         // -#1235
    formatter = new DecimalFormat("'abc'#");
    s = formatter.format(-1234.567);         // -abc1235

[/CODE]

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