Sin[] newlist = new Sin[5];
Sin order1 = new Sin();
int[] _a ={ 100, 200, 300, 400, 500 };
string[] _b ={ "aaa", "vvv", "c", "ddd", "sd" };
string [] _c={"已收","未收","已收","未收","未收"};
for (int i = 0; i < 5; i++)
{
order1.b = _b[i];
order1.a = _a[i];
order1.c = _c[i];
newlist[i] = order1;
}

想把5个order1中的内容放在newlist数组中，可怎么不能放呢？

求解

不可理解newlist[i] = order1？？？

class Sin
{
public object a, b, c;
public Sin()
{
a = new object();
b = new object();
c = new object();
}

}
class Program
{
static void Main(string[] args)
{
Sin[] newlist = new Sin[5];
for(int i=0;i<newlist.Length;i++)
{
newlist[i]=new Sin();
}
Sin order1 = new Sin();
int[] _a ={ 100, 200, 300, 400, 500 };
string[] _b ={ "aaa", "vvv", "c", "ddd", "sd" };
string[] _c ={ "已收", "未收", "已收", "未收", "未收" };
for (int i = 0; i < 5; i++)
{
newlist[i].b =(object) _b[i];
newlist[i].a =(object) _a[i];
newlist[i].c =(object) _c[i];

}
for (int i = 0; i < newlist.Length; i++)
{
Console.WriteLine(newlist[i].a.ToString());
Console.WriteLine(newlist[i].b.ToString());
Console.WriteLine(newlist[i].c.ToString());
}

}
}
你自己看看是否符合你要去

Sin 对象需要写成结构类型的
我同意楼上帅哥的写法