/*输入两个字符串，把含有两个字符串的最小长度的字符串输出．如abc,cde,则输出abcde*/
/*为什么我的这个程序错了呢？*/
/*关于链表我刚在学习，这个程序谁能帮我看看啊，谢谢！*/
#include "stdio.h"
#include "conio.h"
struct link
{
char ch;
struct link *next;
};
struct link *head1,*head2,*pr1,*pr2,*p1,*p2;
main()
{
char c;
head1=(struct link *)malloc(sizeof(struct link));
pr1=head1;
pr2=head2;
printf("Please input the first string:");
while((c=getchar())!='\r')
{
pr1->ch=c;
p1=(struct link *)malloc(sizeof(struct link));
p1->next=NULL;
p1=pr1->next;
pr1=p1;
}
printf("\nPlease input the second string:");
while((c=getchar())!='\r')
{
pr2->ch=c;
p2=(struct link *)malloc(sizeof(struct link));
p2->next=NULL;
p2=pr2->next;
pr2=p2;
}
while(1)
{
while(pr1->ch!=head2->ch&&pr1!=NULL)
{
pr1=pr1->next;
p1=pr1;
}
if(pr1==NULL)
pr1=pr2;
else
T:{
pr1=pr1->next;
pr2=pr2->next;
if(pr2==NULL)
{
pr1=head1;
while(pr1!=NULL)
{
printf("%c",pr1->ch);
pr1=pr1->next;
}
getch();
exit(0);
}
if(pr1==NULL)
{
pr1=pr2->next;
pr1=head1;
while(pr1!=NULL)
{
printf("%c",pr1->ch);
pr1=pr1->next;
}
getch();
exit(0);
}
if(pr1!=NULL&&pr2!=NULL)
{
if (pr2->ch!=pr2->ch)
{
pr1=pr1->next;
continue;
}
else goto T;
}
}
}
getch();
}

建议你看看数据结构
换个方法会好做一点的吧

谢谢先！问题是我正在学，遇到槛上了，能否帮个忙，看下程序？

#include "stdio.h"
#include "conio.h"
struct link
{
char ch;
struct link *next;
};
struct link *head1,*head2,*pr1,*pr2,*p1,*p2;
main()
{
char c;
head1=(struct link *)malloc(sizeof(struct link));
pr1=head1;
pr2=head2;/*这是怎么的,head2指到了哪,你就赋给了pr1/*
printf("Please input the first string:");
while((c=getchar())!='\r')
{
pr1->ch=c;
p1=(struct link *)malloc(sizeof(struct link));
p1->next=NULL;
p1=pr1->next;
pr1=p1;
}
printf("\nPlease input the second string:");
while((c=getchar())!='\r')
{
pr2->ch=c;
p2=(struct link *)malloc(sizeof(struct link));
p2->next=NULL;
p2=pr2->next;
pr2=p2;
}
while(1)
{
while(pr1->ch!=head2->ch&&pr1!=NULL)
{
pr1=pr1->next;
p1=pr1;
}
if(pr1==NULL)
pr1=pr2;
else
T:{
pr1=pr1->next;
pr2=pr2->next;
if(pr2==NULL)
{
pr1=head1;
while(pr1!=NULL)
{
printf("%c",pr1->ch);
pr1=pr1->next;
}
getch();
exit(0);
}
if(pr1==NULL)
{
pr1=pr2->next;
pr1=head1;
while(pr1!=NULL)
{
printf("%c",pr1->ch);
pr1=pr1->next;
}
getch();
exit(0);
}
if(pr1!=NULL&&pr2!=NULL)
{
if (pr2->ch!=pr2->ch)
{
pr1=pr1->next;
continue;
}
else goto T;
}
}
}
getch();
}

我下午写一个今天晚上给你吧

啊，不好意思，加上一句head2=(struct link *)malloc(sizeof(struct link));
输入的时候，它退不出来

乖乖，版主！你在啊，快进来帮忙看下程序！