求助    猜数游戏
代码为猜对或者最多猜10次将退出，

如何更改为猜3次不对就猜下一个数。

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main()
{
    int magic;
    int guess;


    srand(time(NULL));
    magic = rand() % 100 + 1;
    int counter = 0;             //记录人猜次数的计数器变量
    do
    {
        printf("输入一个数：\n");
        scanf_s("%d", &guess);
        counter++;
        if (guess > magic)
        {
            printf("猜大了\n");
        }
        else if (guess < magic)
        {
            printf("猜小了\n");
        }
        else
        {
            printf("对了\n");
            printf("猜了%d次\n", magic);
        }
    } while (guess != magic && counter < 10);//猜对或者猜10次结束



    return 0;
}

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main()
{
    int magic;
    int guess;

    srand(time(NULL));
    magic = rand() % 100 + 1;
    int counter = 0;             //记录人猜次数的计数器变量
    do
    {
        printf("输入一个数：\n");
        scanf("%d", &guess);
        counter++;
        if (guess > magic)
        {
            printf("猜大了\n");
        }
        else if (guess < magic)
        {
            printf("猜小了\n");
        }
        else
        {
            printf("对了\n");
            printf("猜了%d次\n", magic);
            break;
        }
        if(counter==3)//3次后换数
        {
            magic = rand() % 100 + 1;
            counter=0;
        }

    } while (guess!=-1);输入-1退出

    return 0;
}