输入10个同学3门课成绩并保存
计算每门课程的总分和平均分，保存并输出
#include<stdio.h>
#include<stdlib.h>
int main()
{
    int a[10][3]={1,1,1,2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,8,8,8,9,9,9,10,10,10};
    int i,j,k,sum=0;float avg=0;
         /*printf("请输入学生的成绩:");
            for(i=0;i<10;i++)
                for(j=0;j<3;j++)
                    scanf("%d",&a[i][j]);*/
                                    for(j=0;j<3;j++)
                    {
                    for(i=0;i<10;i++)
                    {
                        
                        sum=sum+a[i][0];
                    }
                    avg=sum/10.0;
                    printf("sum=%-3d,avg=%-3f\n",sum,avg);
                     }
    system("pause");
    return main();
}
我计算了一下，算法应该是可以的，但是数值却是sum=55，avg=5.5     sum=110，avg=11     sum=165，avg=16.5
可是应该每一个sum都一样的啊
请大神帮我看看这是为啥

[此贴子已经被作者于2018-12-2 21:11编辑过]

for(i=0,sum=0; i<10; i++)

#include<stdio.h>
#include<stdlib.h>
#define NUMBER 10
#define GRADE 3

int main(void)
{
    int a[GRADE][NUMBER];
    int i, j, sum;
    float avg = 0;

    printf("请输入10名同学第一门课成绩:\n");
    for (i = 0; i < GRADE; i++)
    {
        sum = 0;
        for (j = 0; j < NUMBER; j++)
        {
            scanf("%d", &a[i][j]);
            sum += a[i][j];
        }
        avg = (float)sum / 10.0;
        printf("单门课的总分为:%d,平均分为:%0.2f\n", sum, avg);
        printf("请输入下一门课成绩:\n");
    }

    system("pause");
    return 0;
}

谢谢各位，弄出来了，哈哈