静态成员变量和类型转换构造函数的题,求帮助
代码填空,使得程序能够自动统计当前各种动物的数量,只能在橙色的两句话中间填写代码,红色那一句不知道怎么处理,求大佬看一下。#include <iostream>
using namespace std;
class Animal{
public:
static int number;
};
class Cat{
public:
static int number;
Cat(){
number++;
Animal::number++;
}
~Cat(){
number--;
Animal::number--;
}
};
class Dog{
public:
static int number;
Dog(){
number++;
Animal::number++;
}
~Dog(){
number--;
Animal::number--;
}
};
int Animal::number=0;
int Cat::number=0;
int Dog::number=0;
void print() {
cout << Animal::number << " animals in the zoo, " << Dog::number << " of them are dogs, " << Cat::number << " of them are cats" << endl;
}
int main() {
print();
Dog d1, d2;
Cat c1;
print();
Dog* d3 = new Dog();
Animal* c2 = new Cat;//这里不知道怎么处理实现
Cat* c3 = new Cat;
print();
delete c3;
delete c2;
delete d3;
print();
}
输入
无
输出
0 animals in the zoo, 0 of them are dogs, 0 of them are cats
3 animals in the zoo, 2 of them are dogs, 1 of them are cats
6 animals in the zoo, 3 of them are dogs, 3 of them are cats
3 animals in the zoo, 2 of them are dogs, 1 of them are cats