void inversion_arr(struct Arr *pArr)
{
    int t;
    struct Arr *i;
    struct Arr *j;
    i = pArr;
    j = pArr+pArr->cnt;
    while(i<j)
    {
        t = *i;
        *i = *j;
        *j = t;
        i++;
        j--;
    }

报错：7.cpp
D:\c code\7.cpp(139) : error C2679: binary '=' : no operator defined which takes a right-hand operand of type 'struct Arr' (or there is no acceptable conversion)
D:\c code\7.cpp(141) : error C2679: binary '=' : no operator defined which takes a right-hand operand of type 'int' (or there is no acceptable conversion)
执行 cl.exe 时出错.

7.exe - 1 error(s), 0 warning(s)

赋值两侧类型得一致或者能够自动转换才行啊
你要和大象换位置，它到你的椅子上坐不下呀

哦哦，我明白了，那请问我该怎么改啊，我改成这样好像不对
void inversion_arr(struct Arr *pArr)
{
    int t;
    struct Arr *i;
    struct Arr *j;
    i = pArr;
    j = pArr+pArr->cnt;
    while(i<j)
    {
        t = (int)(*i);
        (int)(*i) = (int)(*j);
        (int)(*j) = t;
        i++;
        j--;
    }

报错：D:\c code\7.cpp(139) : error C2440: 'type cast' : cannot convert from 'struct Arr' to 'int'
        No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
D:\c code\7.cpp(140) : error C2440: 'type cast' : cannot convert from 'struct Arr' to 'int'
        No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
D:\c code\7.cpp(140) : error C2440: 'type cast' : cannot convert from 'struct Arr' to 'int'
        No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
D:\c code\7.cpp(141) : error C2440: 'type cast' : cannot convert from 'struct Arr' to 'int'
        No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
执行 cl.exe 时出错.

7.exe - 1 error(s), 0 warning(s)

2楼的意思是你把结构变量放到 int 变量放不下。。
t 也得是 struct Arr * 类型

[此贴子已经被作者于2018-8-24 22:31编辑过]

类型不一样，怎么能相互赋值呢，尤其还是基本类型对结构体的那种