Oracle 数字查询问题，我的比较笨，求助有没有更好的办法。
存储数据的表 ：TEST， 字段名NUM_ID （为5-13位数字）取出结果存放到表： TEST_NUM
运行环境： ORACLE
要求： 取出NUM_ID的任意6位数满足下列条件之一的所有编号，存入结果表中。
1）ABCDEF 连续递增 2）AAABBB A!=4,B=0,1,2,3,5 3）AAAAAB A!=4, B!=4
以下是我写的代码，在使用to_number()进行递增判断时，会报错：无效数字，所以采用了to_char处理。
程序代码： DECLARE
POS NUMBER;
BEGIN
POS:=1;
FOR POS IN 1 .. 8 LOOP
INSERT INTO TEST_NUM
SELECT T.NUM_ID FROM TEST T WHERE
(
(--ABCDEF '递增'
LENGTH(SUBSTR(T.NUM_ID, POS, 6)) >= 6
AND TO_CHAR(SUBSTR(T.NUM_ID, POS, 6)) IN ('123456', '234567', '345678', '456789','012345')
)
OR
(--AAABBB
LENGTH(SUBSTR(T.NUM_ID, POS, 6)) >= 6
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 1,3)) != '444'
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 4,1)) = TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 5,1))--4=5
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 4,1)) = TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 6,1))--4=6
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 4,1)) IN ('0','1','2','3','5')
)
OR
(--AAAAAB
LENGTH(SUBSTR(T.NUM_ID, POS, 6)) >= 6
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 6,1)) != 4--B!=4
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 1,1)) != 4--A!=4
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 1,1)) = TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 2,1))--1=2
AND TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 1,1)) = TO_CHAR(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 3,1))--1=3
AND SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 1,5) = REVERSE(SUBSTR(SUBSTR(T.NUM_ID, POS, 6), 1,5))--1=5,2=4
)
);
COMMIT;
END LOOP;
END;
