小弟练习时编辑了一段，请问可以更加省略或者简单化吗？


#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]){

        int n;
        int i;
        char **name;

        n=atoi(argv[1]);

        printf("enter %d names :\n",n);

        name=(char**)malloc(sizeof(char*)*n);

        for(i=0;i<n;i++){
                name[i]=(char*)malloc(sizeof(char)*30);
        }

        for(i=0;i<n;i++){
                scanf("%s",name[i]);
        }
      printf("the names you entered :\n");

        for(i=0;i<n;i++){
                printf("%s\n",name[i]);
        }

        return 0;

}

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
    int n,i;
    char **name;
    n=atoi(argv[1]);
    printf("enter %d names :\n",n);
    name=(char**)malloc(sizeof(char*)*n);
    for(i=0;i<n;i++){
        name[i]=(char*)malloc(sizeof(char)*30);
        scanf("%s",name[i]);
    }
    printf("the names you entered :\n");
    for(i=0;i<n;i++){
        printf("%s\n",name[i]);
    }
    free(name);
    return 0;
}

就功能来说:
#include <stdio.h>
#include <stdlib.h>
#define NULL (ushort)0
int main(int argc, char *argv[]){

        int n = 0;
        int i = 0;
        char *name = NULL;
         char *pc = NULL;

        n = atoi(argv[1]);

        printf("enter %d names :\n", n);

        name=(char*)malloc(sizeof(char) * n * （30 + 1)）;

        for(name; name < (pc + (sizeof(char) * n * （30 + 1))); name += (30 + 1))
         {
             if (NULL == pc)
             {
                printf("内存不足！\n");
                n = 0;
                break;
             }
            scanf("%s", pc[i++]);
        }

         printf("the names you entered :\n");
            
        for(i=0; i<n; i++)
         {
            printf("%s\n", pc[i]);
        }

         free (pc);

        return 0;
}