#include<stdio.h>
main()
{
    float A, B, C,m,f;
        char op, ch,hh,M,W,T,F,Y,N;
        printf("please inout your mother and father's hight\n");
        scanf("%f\n%f", &m, &f);
        printf("you are a men(M) or women(W) ?\n");
        scanf("%c", &op);
        if (op == M)A = (m + f)*0.54;
        if (op == W)A = (f*0.923 + m) / 2;
        printf("do you like PE?   (T or F):\n");
        scanf("%c",&ch);
        if (ch == T)B = A*0.02;
        if (ch == F)B = A;
        printf("do you have a good eat habit? (Y or N):\n");
        scanf("%c", &hh);
        if (hh == Y)C = B*0.015;
        if (hh == N)C = B;
        printf("output:%f", C);
        
}

 scanf("%f\n%f", &m, &f);

#include<stdio.h>
main()
{
    float A, B, C,m,f;
        char op, ch,hh,M,W,T,F,Y,N;
        printf("please inout your mother and father's hight\n");
        scanf("%f%f", &m, &f);                 //scanf()中不要有转义字符之类的，没有用
        printf("you are a men(M) or women(W) ?\n");
        fflush(stdin);                //这里     函数的作用你百度一下吧
        scanf("%c", &op);
        if (op == M)A = (m + f)*0.54;
        if (op == W)A = (f*0.923 + m) / 2;
        printf("do you like PE?   (T or F):\n");
        fflush(stdin);       //这里
        scanf("%c",&ch);
        if (ch == T)B = A*0.02;
        if (ch == F)B = A;
        printf("do you have a good eat habit? (Y or N):\n");
        fflush(stdin);      //这里
        scanf("%c", &hh);
        if (hh == Y)C = B*0.015;
        if (hh == N)C = B;
        printf("output:%f", C);
        
}

十幾行運行，就嘗試運行兩三行，運行成功了、達到目的了，再增加行數。這樣的問題都要別人解決了告訴你答案，別學了。當然，我說這些，並不僅僅針對你，而是普遍性的。

[此贴子已经被作者于2015-10-26 20:11编辑过]

#include<stdio.h>
int main()
 {
     float A, B, C,m,f;
         char op, ch,hh,M,W,T,F,Y,N;
         printf("please input your mother and father's hight\n");
         scanf("%f%f", &m, &f);                 
        printf("you are a men(M) or women(W) ?\n");
         fflush(stdin);               
        scanf("%c", &op);
         if (op == 'M' || op=='m')A = (m + f)*0.54;  //判断输入的字符是否与，m相同，要加上  单引号
         if (op == 'W' || op=='w')A = (f*0.923 + m) / 2;
         printf("do you like PE?   (T or F):\n");
         fflush(stdin);      
        scanf("%c",&ch);
         if (ch == 'T' || ch=='t')B = A*0.02;
         if (ch == 'F' || ch=='f')B = A;
         printf("do you have a good eat habit? (Y or N):\n");
         fflush(stdin);      
        scanf("%c", &hh);
         if (hh == 'Y' || hh=='y')C = B*0.015;
         if (hh == 'N' || hh=='n')C = B;
         printf("output:%f", C);
         return 0;
         
 }

十几行都不肯自己动手，看来我还是回水区吧，这里不适合我

我想问一下 这个函数想要求得是什么
为什么结果很不正常

当然不正常
        if (ch == T)B = A*0.02;
        if (ch == F)B = A;
里面的 A*0.02 是否其实是想A * 1.02 ?
否则选T和选F的结果相差很远。。。。

额，自己多看看