题目是一个数如果所有因子之和为其本身则称为完数  要求输出1000以内的完数例如6=1+2+3；则6是完数
输出格式 6 its factor are 1,2,3
#include<stdio.h>
int main()
{
    int a=0,b,c[1000],i,j,k=0,m;
    for(i=2;i<=1000;i++)
    {
        for(j=1;j<i;j++)
        {
            if(i%j==0)
            {
                c[k]=j;
                a=a+c[k];
                k++;
            }
        }
        if(a==i)
        {    printf("%d its factors are ",i);
        for(m=0;m<k;m++)
            printf(",%d",c[m]);
        printf("\n");
        }
        a=0;
    }
    return 0;
}
6 its factors are ,1,1,1,2,1,1,2,3
28 its factors are ,1,1,1,2,1,1,2,3,1,1,2,4,1,3,1,2,5,1,1,2,3,4,6,1,1,2,7,1,3,5,
1,2,4,8,1,1,2,3,6,9,1,1,2,4,5,10,1,3,7,1,2,11,1,1,2,3,4,6,8,12,1,5,1,2,13,1,3,9,
1,2,4,7,14
Press any key to continue
这是我的结果；


答案是
6 its factor are 1,2,3
28 its factor are 1,2,4,7,14
 496 its factor are 1,2,4,8,16,31,62,124,248

for(i=2;i<=1000;i++)
{
k=0;   //在这里加上
for(j=1;j<i;j++)

噢  弄好了  谢谢咯