请大家帮我改改这个程序，搞不懂为什么总得不到正确结果
#include <stdio.h>
#include <string.h>

int main()
{
    int temp;
    int i,max;
    int clength;
    int alength;
    int blength;

    char a[15];
    char b[15];

    char c[15];

    while( (scanf("%s %s",a,b))!=EOF )
    {
        alength=strlen(a);
        blength=strlen(b);

        for(i=0;i<alength/2;i++)        /* 将存储运算数的数组倒置 */
        {
            temp=a[i];
            a[i]=a[alength-i-1];
            a[alength-i-1]=temp;
        }

        //printf("%s\n",a);

        for(i=0;i<blength/2;i++)
        {
            temp=b[i];
            b[i]=b[blength-i-1];
            b[blength-i-1]=temp;
        }

        //printf("%s\n",b);

        if(alength>blength)                /* 若两个运算数长度不相等，则用'0'将较短的字符数组补齐 */
        {
            max=alength;

            for(i=blength;i<max;i++)
            {
                b[blength]='0';
            }

            b[max-1]='\0';
        }
        else
        {
            max=blength;

            for(i=alength;i<max;i++)
            {
                a[blength]='0';
            }

            a[max-1]='\0';
        }

        for(i=0;i<=max;i++)
        {
            c[i]='0';
        }

        for(i=0;i<max;i++)                    /* 计算结果存储于字符数组c中 */
        {
            c[i]+=a[i]+'0'+b[i]+'0';

            if(c[i]>'9')                    /* 判断是否有进位 */
            {
                c[i]-=10;
                c[i+1]='1';
            }
        }
            if(c[max]>'0')
            {
                c[max+1]='\0';
                clength=max;
            }
            else
            {
                c[max]='\0';
                clength=max-1;
            }

            for(i=0;i<clength/2;i++)            /* 将字符数组倒置，得到运算结果 */
            {
                temp=c[i];
                c[i]=c[clength-1-i];
                c[clength-1-i]=temp;
            }

            printf("%s\n",c);
        }

    return 0;
}

你的加法和进位处理都有问题，我试着改了一下。你对照一下。
#include <stdio.h>
#include <string.h>

int main()
{
    int temp;
    int i,max;
    int clength;
    int alength;
    int blength;

    char a[150];
    char b[150];

    char c[150];

    while( (scanf("%s %s",a,b))!=EOF )
    {
        alength=strlen(a);
        blength=strlen(b);

        for(i=0;i<alength/2;i++)        /* 将存储运算数的数组倒置 */
        {
            temp=a[i];
            a[i]=a[alength-i-1];
            a[alength-i-1]=temp;
        }

        //printf("%s\n",a);

        for(i=0;i<blength/2;i++)
        {
            temp=b[i];
            b[i]=b[blength-i-1];
            b[blength-i-1]=temp;
        }

        //printf("%s\n",b);

        if(alength>blength)                /* 若两个运算数长度不相等，则用'0'将较短的字符数组补齐 */
        {
            max=alength;

            for(i=blength;i<max;i++)
            {
                b[i]='0';
            }

            b[max]='\0';
        }
        else
        {
            max=blength;

            for(i=alength;i<max;i++)
            {
                a[i]='0';
            }

            a[max]='\0';
        }

        for(i=0;i<=max+1;i++)
        {
            c[i]=0;
        }



        for(i=0;i<max;i++)                    /* 计算结果存储于字符数组c中 */
        {
            c[i]+=a[i]+b[i]-2*'0';

            if(c[i]>9)                    /* 判断是否有进位 */
            {
                c[i]-=10;
                c[i+1]=1;
            }
            c[i]+='0';
        }
            if(c[max]!=0)
            {
                c[max]+='0';     
            }
            clength= strlen(c);
            

            for(i=0;i<clength/2;i++)            /* 将字符数组倒置，得到运算结果 */
            {
                temp=c[i];
                c[i]=c[clength-1-i];
                c[clength-1-i]=temp;
            }

            printf("%s\n",c);
        }

    return 0;
}

谢谢啦，我回去研究研究。