想请问各位如何才能做到像以下样本程序那样，本人能做到一步一步显示出来罢了。还有写什么代码才能计算每次移动的步速？还有我是用Dev C++这个软件编写的。
本人是C语言初学者，恳求解答，谢谢各位。

#include <stdio.h>
#include <dos.h>
#include <stdlib.h>
#define XMAX 10
#define YMAX 10

char maze[XMAX][YMAX] = {
        "XXXXXXXXXX",
        "X  X X X X",
        "XX X   X X",
        "XX XXX   X",
        "X    X XXX",
        "XX X X XEX",
        "X  X   X X",
        "XX XXX X X",
        "XS   X   X",
        "XXXXXXXXXX"
};
char mazes[XMAX][YMAX] = {
        "XXXXXXXXXX",
        "X  X X X X",
        "XX X   X X",
        "XX XXX   X",
        "X    X XXX",
        "XX X X XEX",
        "X  X   X X",
        "XX XXX X X",
        "XS   X   X",
        "XXXXXXXXXX"
};

int goAhead(void);
int goBack(void);
void printMaze(void);
void printMazes(void);
int mazeWalk(int x, int y);
int mazeBack(int x, int y);

int main(void){        
    goAhead();
    goBack();
    getchar();
    return(0);
}

int goAhead(void){
    int x, y, sum;
    char abc;
    for (x=0; x<XMAX; x++)
        for (y=0; y<YMAX; y++)
            if (maze[x][y]=='S')
                if(!mazeWalk(x,y))
                    puts("No route to [E]xit from [S]tart.");
    printMaze();
    printf("\n");    
    sum=mazeWalk(x,y);
    printf("\n%d steps are used.\n", &sum);

    printf("Press Enter to continue for E to S");
    scanf("%c", &abc);
}

int goBack(void){
    int x, y;
    for (x=0; x<XMAX; x++)
        for (y=0; y<YMAX; y++)
            if (mazes[x][y]=='E')
                if(!mazeBack(x,y))
                    puts("No route to [S]tart from [E]xit.");
        printMazes();
}

void printMaze(void){
    int x, y;
    for (x=0; x<XMAX; x++){
        for (y=0; y<YMAX; y++)putchar(maze[x][y]);
        putchar('\n');
    }
}
void printMazes(void){
    int x, y;
    for (x=0; x<XMAX; x++){
        for (y=0; y<YMAX; y++)putchar(mazes[x][y]);
        putchar('\n');
    }
}

int mazeWalk(int x, int y){

    if (maze[x][y]=='E')return(1);
                                  
    if ((maze[x][y+1]==' ')||(maze[x][y+1]=='E')){
        maze[x][y]='>';
            printMaze();
            sleep(1);
            
    printf("\n");
        if(mazeWalk(x,y+1))
           return(1);
    }

if ((maze[x-1][y]==' ')||(maze[x-1][y]=='E')){
        maze[x][y]='^';

        if(mazeWalk(x-1,y))return(1);
    }
    if ((maze[x][y-1]==' ')||(maze[x][y-1]=='E')){
        maze[x][y]='<';

        if(mazeWalk(x,y-1))return(1);
    }
    if ((maze[x+1][y]==' ')||(maze[x+1][y]=='E')){
        maze[x][y]='V';

        if(mazeWalk(x+1,y))return(1);
    }
    maze[x][y]=' ';
        printMaze();
            printf("\n");
        sleep(1);

    return(0);
}

int mazeBack(int x, int y){

    if (mazes[x][y]=='S')return(1);

    if ((mazes[x][y+1]==' ')||(mazes[x][y+1]=='S')){
        mazes[x][y]='>';
        printMazes();
        sleep(1);
        printf("\n");
        
        if(mazeBack(x,y+1))
           return(1);
    }

if ((mazes[x-1][y]==' ')||(mazes[x-1][y]=='S')){
        mazes[x][y]='^';

        if(mazeBack(x-1,y))return(1);
    }
    if ((mazes[x][y-1]==' ')||(mazes[x][y-1]=='S')){
        mazes[x][y]='<';
                
        if(mazeBack(x,y-1))return(1);
    }
    if ((mazes[x+1][y]==' ')||(mazes[x+1][y]=='S')){
        mazes[x][y]='V';
                
        if(mazeBack(x+1,y))return(1);
    }
    mazes[x][y]=' ';
            printMazes();
                printf("\n");
        sleep(1);
    return(0);
}
/* maze.c : end of code */

[ 本帖最后由 察而斯 于 2014-1-13 22:13 编辑 ]

嘿嘿
我是纯粹来学习的