#include<stdio.h>
#include<string.h>
int main()
{
  char s1[12][5]={"I","II","III","IV","V","VI","V","VII","VIII","IX","X","XI","XII"};
   char (*p)[12]=s1[0],s2,j;
   int i=0;
   scanf("%s",s2);
    for(i=0;i<12;i++)
    for(j=0;j<=4;j++)
    {
      if(strcmp(s2,*(*（p+i）+j))==0)
       {
           printf("%d",i+1);
       break;

       }
       else
         *p++;
        }
  return 0;
    }

#include<stdio.h>
#include<string.h>
void main()
{char s1[12][5]={"I","II","III","IV","V","VI","VII","VIII","IX","X","XI","XII"};
char (*p)[5]=s1,s2[5];
printf("请输入:");
gets(s2);
do
{if(strcmp(*p,s2)==0)
    {printf("%d\n",p-s1+1);break;}
}while(strcmp(*p++,"XII")!=0);
}
兄弟，看个更简洁的。

[ 本帖最后由 bccn新 于 2013-6-2 20:17 编辑 ]

s2是char，只能接收1个字符，要定义成数组。
数组名其实就是个指针。

#include<stdio.h>
#include<string.h>
int main()
{
    char s1[][5]= {"I","II","III","IV","V","VI","VII","VIII","IX","X","XI","XII"};
    char s2[5];
    int i=0;
    scanf("%s",s2);
    for(i=0; i<12; i++)
    {
        if(strcmp(s2,s1[i])==0)
        {
            printf("%d",i+1);
            break;
        }
    }
    return 0;
}

你的 char s1[12][5] 多了个 "V"