1.    通过cin输入两个时，分，秒数据。计算出每一时，分，秒距离0时0分0秒的总秒数。并求两个总秒数差的绝对值

跟隔壁你自己承认的一样，这是数学问题，补习一下数学嘛。

#include <iostream>
 
using namespace std;
 
int main()
 {
     int s,f,m,s1,f1,m1,sum1,sum2,bad;
     cout<<"请输入6个整数:"<<endl;
     cin s,f,m,s1,f1,m1;
     sum1=s*3600+f*60+m;
     sum2=s1*3600+f2*60+m2;
     dan=sum1-sum2;
      cout<<"The sum1 of "<<s<<" , "<<f<<" and "<<m<<" is:"<<sum1<<endl;
 cout<<"the sum2 of"<<s1<<","<<f1<<"and"<<m1<<"is"<<sum2<<endl;
cout<<"the bad of"<<sum1<<","<<sum2<<"and"<<"is"<<bad<<endl;
     return 0;
纠正一下，谁帮我，，，才上几节课，，，什么都不懂

#include <iostream>
 
using namespace std;
 
int main()
 {
     int s,f,m,s1,f1,m1,sum1,sum2,bad;
     cout<<"请输入6个整数:"<<endl;
     cin s,f,m,s1,f1,m1;
     sum1=s*3600+f*60+m;
     sum2=s1*3600+f2*60+m2;
     dan=sum1-sum2;
      cout<<"The sum1 of "<<s<<" , "<<f<<" and "<<m<<" is:"<<sum1<<endl;
 cout<<"the sum2 of"<<s1<<","<<f1<<"and"<<m1<<"is"<<sum2<<endl;
cout<<"the bad of"<<sum1<<","<<sum2<<"and"<<"is"<<bad<<endl;
     return 0;
怎么无法执行啊？

你看看cin的语法

cin的语法    ？？？

都说了才学的嘛，不懂，讲仔细点嘛

cout<<"The sum1 of "<<s<<" , "<<f<<" and "<<m<<" is:"<<sum1<<endl;
 cout<<"the sum2 of"<<s1<<","<<f1<<"and"<<m1<<"is"<<sum2<<endl;
 cout<<"the bad of"<<sum1<<","<<sum2<<"and"<<"is"<<bad<<endl;
这儿有什么简单的写法嘛。帮下啊

写到这份上已不是什么都不懂了，静下心来，很快就成了，学习过程比结果重要