程序代码:
怎么打开用GetFile()取得的文件[原创:流星雨]? FileName=GETFILE() DoOut(0,'OPEN',JUSTFNAME(FileName),'',JUSTPATH(FileName),9) *------------------------------------------------------------------------------------------ FUNCTION DoOut PARAMETERS lnHwnd,lcCom,lcFile,LcPra,lcPath,lcMode DECLARE INTEGER ShellExecute IN "Shell32.dll" INTEGER hwnd,STRING,STRING,STRING,STRING,LONG Shellexecute(lnHwnd,lcCom,lcFile,LcPra,lcPath,lcMode) CLEAR DLLS "ShellExecute" ENDPROC试试这个
坚守VFP最后的阵地