#include<iostream>
#include<stdio.h>
int main(int argc,char*argv[])
{
    int c,d;
    char e;
    char*p;
    p=argv;
    c=number(p);
    e=*p;
    d=number(p);
    Result();
}
int number(char*p)
{
    int sum=0,m;
    while(*p>='0'&&*p<='9')
    {
        m=*p;
        sum=sum*10+m;
        p++;
    }
    p++;
    return sum;
}
void Result(char e)
{
    int result;
    switch(e)
    {
    case '+':
        result=c+d;
        cout<<result<<endl;
        break;
    case '-':
        result=c-d;
        cout<<result<<endl;
        break;
    case '*':
        result=c*d;
        cout<<result<<endl;
        break;
    case '/':
        if(d==0)
        {
            cout<<error!!!<<endl;
            break;
        }
        else
        {
            result=c/d;
            cout<<result<<endl;
            break;
        }
    default:
        cout<<"error"<<endl;
    }
}

没想法。。。

#include<iostream>
#include<stdio.h>
char* number(int &c,char *p);
void Result(char e,int c,int d);

int main(int argc,char *argv[])
{
    int c,d;
    char e;
    char*p;
    p=argv[1];
    p=number(c,p);
    e=*p;
    p++;
    number(d,p);
    Result(e,c,d);
}
char* number(int &c,char *p)
{
    int sum=0,m;
    while(*p>='0'&&*p<='9')
    {
        m=*p;
        sum=sum*10+m;
        p++;
    }
    c=sum;
     return p;
}
void Result(char e,int c,int d)
{
    int result;
    switch(e)
    {
    case '+':
        result=c+d;
        cout<<result<<endl;
        break;
    case '-':
        result=c-d;
        cout<<result<<endl;
        break;
    case '*':
        result=c*d;
        cout<<result<<endl;
        break;
    case '/':
        if(d==0)
        {
            cout<<error!!!<<endl;
            break;
        }
        else
        {
            result=c/d;
            cout<<result<<endl;
            break;
        }
    default:
        cout<<"error"<<endl;
    }
}
试一下这个

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