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标题:华山论剑 之 [矩阵]
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zhang7986437
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大家好,我是一位编程初学者,请多多关照
2012-08-13 20:45
acmiler
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我刚刚学C语言  不是很懂 不过我会努力的 嘿嘿!争取把你这帖子看懂啊!
2012-08-14 16:25
Bob2012
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欣赏也是一种艺术

艺多不压身 爱你们就想日后驾御你们!
2012-08-15 01:17
guiyi
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2012-08-16 18:02
beyondyf
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久等了,奉上我的代码。其它部分都比较容易理解,只有矩阵乘法比较难一点,所以加了点注释。
欢迎批评指正。
程序代码:
#include<stdio.h>
#include<math.h>

#define DOUBLE_LIMIT    1.0E-300

typedef struct matrix_element_node
{
    double data;
    int col;
    struct matrix_element_node * next;
}MATRIX_ELEMENT;

typedef struct matrix
{
    MATRIX_ELEMENT * r;
    int rows;
    int columns;
}MATRIX;

MATRIX * Matrix_create(int rows, int columns);//创建rows行columns列矩阵,元素初始值为0
void Matrix_free(MATRIX * mat);//销毁mat矩阵
int Matrix_rows_len(MATRIX * mat);//获取矩阵mat的行数,mat为空指针时返回0
int Matrix_cols_len(MATRIX * mat);//获取矩阵mat的列数,mat为空指针时返回0
int Matrix_set(MATRIX * mat, int row, int column, double value);//设置mat矩阵第row行第column列的元素值为value,操作成功返回0,否则返回一个非0值
double Matrix_get(MATRIX * mat, int row, int column);//获取mat矩阵第row行第column列的元素值
MATRIX * Matrix_add(MATRIX * mat1, MATRIX * mat2);//计算两个矩阵相加,返回和矩阵。当两个矩阵不能作加法运算时返回NULL
MATRIX * Matrix_mul(MATRIX * mat1, MATRIX * mat2);//计算两个矩阵相乘,注意是mat1左乘mat2。如果不能作乘法运算返回NULL
MATRIX * Matrix_mul_real(MATRIX * mat, double a);//计算矩阵与实数相乘
MATRIX * Matrix_dot_mul(MATRIX * mat1, MATRIX * mat2);//计算两个矩阵的点乘。如果不能作运算返回NULL
MATRIX * Matrix_trans(MATRIX * mat);//返回mat的转置矩阵
void Matrix_print(MATRIX * mat);

int main()
{
    MATRIX * a, * b, * c;
    int i, j;
    a = Matrix_create(3, 3);
    b = Matrix_create(3, 3);
    for(i = 0; i < 3; i++)
    for(j = 0; j < 3; j++)
    {
        Matrix_set(a, i, j, i * 3 + j + 1);
        Matrix_set(b, i, j, 9 - i * 3 - j);
    }
   
    printf("a = \n");
    Matrix_print(a);
   
    printf("b = \n");
    Matrix_print(b);
   
    printf("a + b = \n");
    c = Matrix_add(a, b);
    Matrix_print(c);
   
    printf("a * b = \n");
    Matrix_free(c);
    c = Matrix_mul(a, b);
    Matrix_print(c);
   
    printf("a * 2.5 = \n");
    Matrix_free(c);
    c = Matrix_mul_real(a, 2.5);
    Matrix_print(c);

    printf("a .* b = \n");
    Matrix_free(c);
    c = Matrix_dot_mul(a, b);
    Matrix_print(c);
   
    printf("a' = \n");
    Matrix_free(c);
    c = Matrix_trans(a);
    Matrix_print(c);
   
    Matrix_free(a);
    Matrix_free(b);
    Matrix_free(c);
    return 0;
}

MATRIX * Matrix_create(int rows, int columns)
{
    MATRIX * p;
    int i;
   
    p = (MATRIX *)malloc(sizeof(MATRIX));
    p->r = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT) * rows);
    for(i = 0; i < rows; p->r[i++].next = NULL);
    p->rows = rows;
    p->columns = columns;
    return p;
}

void Matrix_free(MATRIX * mat)
{
    MATRIX_ELEMENT * e, * t;
    int i;
   
    for(i = 0; i < mat->rows; i++)
    for(e = mat->r[i].next; e != NULL; free(t)) t = e, e = e->next;
    free(mat->r);
    free(mat);
}

int Matrix_rows_len(MATRIX * mat)
{
    return mat->rows;
}

int Matrix_cols_len(MATRIX * mat)
{
    return mat->columns;
}

int Matrix_set(MATRIX * mat, int row, int column, double value)
{
    MATRIX_ELEMENT * pre, * e, * t;
   
    if(mat == NULL || row < 0 || row >= mat->rows || column < 0 || column >= mat->columns) return 1;
    for(pre = &(mat->r[row]), e = pre->next; e != NULL && e->col < column; pre = e, e = e->next);
    if(fabs(value) < DOUBLE_LIMIT)
    {
        if(e != NULL && e->col == column)
        {
            pre = e->next;
            free(e);
        }
    }
    else
    {
        if(e != NULL && e->col == column)
        {
            e->data = value;
        }
        else
        {
            t = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT));
            t->data = value;
            t->col = column;
            t->next = e;
            pre->next = t;
        }
    }   
    return 0;
}

double Matrix_get(MATRIX * mat, int row, int column)
{
    MATRIX_ELEMENT * e;
   
    if(mat == NULL) return 0;
    for(e = mat->r[row].next; e != NULL && e->col < column; e = e->next);
    return (e != NULL && e->col == column) ? e->data : 0;
}

MATRIX * Matrix_add(MATRIX * mat1, MATRIX * mat2)
{
    MATRIX * mat;
    MATRIX_ELEMENT * pre, * e1, * e2, * e, * t;
    double value;
    int col, i;
   
    if(mat1 == NULL || mat2 == NULL || mat1->rows != mat2->rows || mat1->columns != mat2->columns) return NULL;
    mat = Matrix_create(mat1->rows, mat1->columns);
    for(i = 0; i < mat->rows; i++)
    {
        e1 = mat1->r[i].next;
        e2 = mat2->r[i].next;
        pre = &(mat->r[i]);
        while(e1 != NULL && e2 != NULL)
        {
            if(e1->col < e2->col)
            {
                value = e1->data;
                col = e1->col;
                e1 = e1->next;
            }
            else if(e1->col > e2->col)
            {
                value = e2->data;
                col = e2->col;
                e2 = e2->next;
            }
            else
            {
                value = e1->data + e2->data;
                col = e1->col;
                e1 = e1->next;
                e2 = e2->next;
                if(fabs(value) < DOUBLE_LIMIT) continue;
            }
            t = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT));
            t->data = value;
            t->col = col;
            pre->next = t;
            pre = t;
        }
        for(e = (e1 != NULL) ? e1 : e2; e != NULL; e = e->next)
        {
            t = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT));
            t->data = e->data;
            t->col = e->col;
            pre->next = t;
            pre = t;
        }
        pre->next = NULL;
    }
    return mat;
}

MATRIX * Matrix_mul(MATRIX * mat1, MATRIX * mat2)
{
    MATRIX * mat;
    MATRIX_ELEMENT ** pre;    //mat矩阵的列元素指针数组,每个元素指向每行的最后一个元素结点
    MATRIX_ELEMENT * mr;      //mat1矩阵的行指针,指向mat1的计算行的结点
    MATRIX_ELEMENT **mc;      //mat2矩阵的列元素指针数组,每个元素指向mat2的计算列的结点
    MATRIX_ELEMENT *t;        //临时指针,用于分配新申请的结点内存
    int i, j, count;          //count为mat2待计算列中的结点数量
    double value;
   
    if(mat1 == NULL || mat2 == NULL || mat1->columns != mat2->rows) return NULL;
   
    mat = Matrix_create(mat1->rows, mat2->columns);
    pre = (MATRIX_ELEMENT **)malloc(sizeof(MATRIX_ELEMENT *) * mat->rows);
    mc = (MATRIX_ELEMENT **)malloc(sizeof(MATRIX_ELEMENT *) * mat2->rows);

    for(count = i = 0; i < mat2->rows; i++)
        if((mc[i] = mat2->r[i].next) != NULL) count++;
   
    if(count == 0)
    {
        free(pre);
        free(mc);
        return mat;
    }
   
    for(i = 0; i < mat->rows; i++) pre[i] = &(mat->r[i]);
   
    //计算过程是按列优先进行的
    //举例说明:矩阵下标从0开始计数
    //一般的计算习惯是按行优先的,如先计算[0,0],[0,1],[0,2]...,再计算[1,0],[1,1],[1,2]...
    //这里的计算过程是先计算[0,0],[1,0],[2,0]...,再计算[0,1],[1,1],[2,1]...
    //选择这种计算顺序是为了减少计算过程中对mat2矩阵元素检索所需要的指针移动次数,提高计算效率
    for(j = 0; count > 0 && j < mat->columns; j++)
    {
        for(i = 0; i < mat->rows; i++)
        {
            value = 0;
            for(mr = mat1->r[i].next; mr != NULL; mr = mr->next)
                if(mc[mr->col] != NULL && mc[mr->col]->col == j)
                    value += mr->data * mc[mr->col]->data;

            if(fabs(value) < DOUBLE_LIMIT) continue;
            t = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT));
            t->data = value;
            t->col = j;
            t->next = NULL;
            pre[i]->next = t;
            pre[i] = t;
        }
        for(i = 0; i < mat2->rows; i++)
        {
            if(mc[i] == NULL) continue;
            if(mc[i]->col <= j) mc[i] = mc[i]->next;
            if(mc[i] == NULL) count--;
        }
    }
    free(pre);
    free(mc);
    return mat;
}

MATRIX * Matrix_mul_real(MATRIX * mat, double a)
{
    MATRIX * new_mat;
    MATRIX_ELEMENT * pre, * e, * t;
    double value;
    int i;
   
    if(mat == NULL) return NULL;
    new_mat = Matrix_create(mat->rows, mat->columns);
    for(i = 0; i < mat->rows; i++)
    for(pre = &(new_mat->r[i]), e = mat->r[i].next; e != NULL; e = e->next)
    {
        value = e->data * a;
        if(fabs(value) < DOUBLE_LIMIT) continue;
        t = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT));
        t->data = value;
        t->col = e->col;
        t->next = NULL;
        pre->next = t;
        pre = t;
    }
    return new_mat;
}

MATRIX * Matrix_dot_mul(MATRIX * mat1, MATRIX * mat2)
{
    MATRIX * mat;
    MATRIX_ELEMENT * pre, * e1, * e2, * t;
    double value;
    int i;
   
    if(mat1 == NULL || mat2 == NULL || mat1->rows != mat2->rows || mat1->columns != mat2->columns) return NULL;
    mat = Matrix_create(mat1->rows, mat1->columns);
    for(i = 0; i < mat->rows; i++)
    {
        pre = &(mat->r[i]);
        e1 = mat1->r[i].next;
        e2 = mat2->r[i].next;
        while(e1 != NULL && e2 != NULL)
        {
            if(e1->col < e2->col){ e1 = e1->next; continue;}
            if(e1->col > e2->col){ e2 = e2->next; continue;}
            value = e1->data * e2->data;
            if(fabs(value) < DOUBLE_LIMIT) continue;
            t = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT));
            t->data = value;
            t->col = e1->col;
            pre->next = t;
            pre = t;
            e1 = e1->next;
            e2 = e2->next;
        }
        pre->next = NULL;
    }
    return mat;
}

MATRIX * Matrix_trans(MATRIX * mat)
{
    MATRIX * new_mat;
    MATRIX_ELEMENT ** pre, * e, * t;
    int i;
   
    if(mat == NULL) return NULL;
    new_mat = Matrix_create(mat->columns, mat->rows);
    pre = (MATRIX_ELEMENT **)malloc(sizeof(MATRIX_ELEMENT *) * new_mat->rows);
    for(i = 0; i < new_mat->rows; i++) pre[i] = &(new_mat->r[i]);
   
    for(i = 0; i < mat->rows; i++)
    for(e = mat->r[i].next; e != NULL; e = e->next)
    {
        t = (MATRIX_ELEMENT *)malloc(sizeof(MATRIX_ELEMENT));
        t->data = e->data;
        t->col = i;
        t->next = NULL;
        pre[e->col]->next = t;
        pre[e->col] = t;
    }
    free(pre);
    return new_mat;
}

void Matrix_print(MATRIX * mat)
{
    MATRIX_ELEMENT * e;
    int i, j;
    for(i = 0; i < mat->rows; i++, puts("\n"))
    for(j = 0; j < mat->columns; j++)
    printf("%10.2f", Matrix_get(mat, i, j));
}

重剑无锋,大巧不工
2012-08-16 20:03
有容就大
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回复 75楼 beyondyf
终于看到杨大哥的代码了 确实高水平 慢慢揣摩。

梅尚程荀
马谭杨奚







                                                       
2012-08-16 22:20
喝醉的猫
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呵呵看看
2012-08-29 11:01
快速回复:华山论剑 之 [矩阵]
数据加载中...
 
   



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