#include<stdio.h>
int main()
{
    int m, n, i, line[104], s, j, h;
    int aver1, aver2;
    while( scanf( "%d%d",&m,&n ) != EOF )
    {

        line[0] = 2;
        for( i = 1; i < n; i++ )
            line[i] = line[i-1] + 2;
        h = n % m;
        for( j = 0; j < n / m; j++ )
        {
             s = 0;
             for( i = j * m; i < ( j + 1) * m; i++ )
                 s = s + line[i];
             aver1 = s / m;
             if( j == 0 )
                printf( "%d",aver1);
             else
             printf( " %d", aver1);

        }
        if( h != 0)
        {
            s = 0;
            for( i = n - h; i < n ; i++ )
            s = s + line[i];
            aver2 = s / h;
            printf( " %d",aver2 );
        }
        printf( "\n");
    }
    return 0;

}
_____________________________________________________________________________________________________________________
#include<stdio.h>
int main()
{
    int m,n,i,line[104],s,j,h;
    int aver1,aver2;
    while( scanf( "%d%d",&n,&m ) != EOF )
    {
        line[0]=2;
        for( i = 1; i < n; i++ )
            line[i]=line[i-1]+2;
        h = n % m;//这是什么
        for( j = 0; j < n / m; j++ )//为什么要是n/m
        {
            s = 0;
            for( i = j * m; i < (j+1) * m; i++ )//好复杂，没看懂
                s = line[i] + s;
            aver1 = s / m;
            if( j == 0 )
                printf( "%d",aver1 );
            else printf( " %d",aver1 );
        }
        if( h != 0 )
        {
            s = 0;
            for( i = n - h; i < n;i++ )
                s = s + line[i];
            aver2 = s / h;
            printf( " %d",aver2 );
        }
        printf( "\n" );
    }
    return 0;
}

呵呵，靠调试应该就可以看出来。
两个输入变量反了
while( scanf( "%d%d",&m,&n ) != EOF )
while( scanf( "%d%d",&n,&m ) != EOF )

谢谢指教，还有一个问题，为什么先输入m和先输入n的结果不一样呢

原理都一样 程序也没问题 对应每对n m， 输出的结果是正确的。