题目要求：输入一个四位数，和电脑产生的一个四位数字相比较，这里假设是1352。如果数字相等且位置一样，用A表示；若数字相同位置不同用B表示。例如输入1234，结果输出1A2B。下面的程序经过改过之后的，我希望在“do you want to continue " 后输入'y'在继续执行~~~可是不知道如何返回~~

#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <time.h>
#include <process.h>
void main()
{
int answer[4],i,j,guess=0,a,b,times=0;
char c;

for(i=0;i<4;i++)
{
srand((unsigned)time(NULL));
answer[i]=rand()%10;
for(j=0;j<i;j++)
{
while(answer[i]==answer[j])
{
answer[i]=rand()%10;
j=-1;
}
}
}

printf("Please guess:\n");

while(a!=4)
{
a=0;
b=0;
times++;
do
{
printf("%-4d",times);
scanf("%d",&guess);
if(guess==0)
exit(0);
}while(guess<0||guess>9999);

for(i=3;i>-1;i--)
{
for(j=0;j<4;j++)
if((int)(guess/pow(10,i))==answer[j])
{
if(i+j==3)
a=a+1;
else
b=b+1;
}
guess=guess-(int)(guess/pow(10,i))*pow(10,i);
}
printf(" %dA%dB\n",a,b);
}

printf("congratulation to you!\n");
printf("you take %d times to guess right!\n",times);
printf("this time generated number is:\n");

for(i=0;i<4;i++)
printf("%3d",answer[i]);
printf("\n");

printf("do you want to continue(y/n)?");
scanf("%c",&c);
if(c=='y')
返回程序重新开始；//关键是这里如何返回,我用goto语句好像不行啊
else
exit(0);

}

[此贴子已经被作者于2005-12-5 18:10:59编辑过]

有几处小错误

[此贴子已经被作者于2005-12-5 0:31:11编辑过]

改了后可以运行

[此贴子已经被作者于2005-12-5 0:30:34编辑过]

共三处小错误for(i=3;i>-1;j++)→for(i=3;i>-1;i--)
if((int)(guess/pow(10,i)==answer[j]))→ if((int)(guess/pow(10,i))==answer[j])
getch()应该放在while循环的外面

谢谢你了~~

#include <stdio.h>
#include <conio.h>
#include <math.h>
#include <stdlib.h>
#include <time.h>
#include <process.h>
void Guess(void);

void main()
{
char c;

Guess();
loop: printf("do you want to continue(y/n)?\n");
c=getch();

if(c=='y')
{
Guess();
goto loop;
}
else
printf("bye.\n");
getch();
return;
}

void Guess(void)
{
int answer[4],i,j,guess=0,a,b,times=0,flag=0;

for(i=0;i<4;i++)
{
srand((unsigned)time(NULL));
answer[i]=rand()%10;

for(j=0;j<i;j++)
{
while(answer[i]==answer[j])
{
answer[i]=rand()%10;
j=-1;
}
}
}

printf("Please guess:\n");

while(a!=4)
{
a=0;
b=0;
times++;

do
{
printf("%-4d",times);
scanf("%d",&guess);

if(guess<0||guess>9999)
{
printf(" please guess again: \n"); //这里修改是为了假如猜出范围 就出现提示，并把猜的次数加一。
flag=1;
times++;
}
else
flag=0;
} while(flag);

for(i=3;i>-1;i--)
{
for(j=0;j<4;j++)
if((int)(guess/pow(10,i))==answer[j])
{
if(i+j==3)
a=a+1;
else
b=b+1;
}
guess=guess-(int)(guess/pow(10,i))*pow(10,i);
}
printf(" %dA%dB\n",a,b);
}

printf("congratulation to you!\n");
printf("you take %d times to guess right!\n",times);
printf("this time generated number is:\n");

for(i=0;i<4;i++)
printf("%3d",answer[i]);
printf("\n");
}

TC下运行过了，可连续猜n个回合，只是有些麻烦

[此贴子已经被作者于2005-12-6 13:32:50编辑过]

用时间做随机种子，这里会多运行几个回合（因为这样的话种子精度为55ms），直到种子变化

可以考虑把srand((unsigned)time(NULL));放在 for(i=0;i<4;i++)外面的上一行

feng1256,很感谢你的帮助~
我已经把这个程序改进了，我现在把源程序再发一遍~
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <time.h>
#include <process.h>
static int n=0;
void main(void)
{
int answer[4],i,j,guess=0,a,b,times=0,f,d,t[4];
char c;

while(!n)
{

for(i=0;i<4;i++) /*开始猜数字游戏*/
{
srand((unsigned)time(NULL));
answer[i]=1+rand()%9; /*产生1~9的随机数*/
for(j=0;j<i;j++)
{
while(answer[i]==answer[j])
{
answer[i]=rand()%10;
j=-1;
}
}
}
loop: printf("Please guess:\n");

while(a!=4)
{
a=0;
b=0;
times++;
do
{
printf("%-4d",times);
scanf("%d",&guess);
if(guess==0) /*判断是否字符*/
exit(0);
}while(guess<1000||guess>9999);

f=guess;
for(i=3;i>-1;i--)
{
t[3-i]=(int)guess/pow(10,i);
guess=guess-(int)(guess/pow(10,i))*pow(10,i);
}

for(i=0;i<4;i++) /*如果输入的四位数有相同数字则重新输入*/
for(j=i+1;j<4;j++)
{
if(t[i]==t[j])
{
clrscr();
times=0;
goto loop;
}
}
guess=f;
for(i=3;i>-1;i--)
{
for(j=0;j<4;j++)
if((int)(guess/pow(10,i))==answer[j])/*比较第一位，相等则继续，
不等则比较下一位*/
{
if(i+j==3) /*位置一样则a+1*/
a=a+1;
else /*位置不一样则b+1*/
b=b+1;
}
guess=guess-(int)(guess/pow(10,i))*pow(10,i);/*开始下一位比较*/
}
printf(" %dA%dB\n",a,b);
}

printf("congratulation to you!\n");
printf("you take %d times to guess right!\n",times);
/* printf("this time generated number is:\n");

for(i=0;i<4;i++)
printf("%3d",answer[i]);
printf("\n"); */

fflush(stdin); /*清除键盘缓冲区*/

printf("do you want to continue(y/n)?");
scanf("%c",&c);
if(c=='y')
{
guess=0;
a=0;
b=0;
times=0;
n=0;
}
else if(c=='n')
{
n=1;
printf("welcome next time!\n");
}
}
getch();
}