题目：http://acm.fzu.
这是代码
#include <stdio.h>
int main()
{
    float a;int i;
    float s[281];   
    s[0]=0;   
    for (i=1;i<=280;i++)
        s[i]=s[i-1]+1.0/(i+1);   
    while (scanf("%f",&a)!=EOF)
    {
        
        if(a==0.00) break;
        else
            for (i=1;i<=280;i++)
        {
            if(a<=s[i]) break;
        }
        printf("%d card(s)\n",i);
    }
    return 0;
}
怎么提交都是WA
ac大神救命那

input：Each test case is a single line containing a positive floatingpoint number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits。
所以for (i=1;i<=280;i++)
        s[i]=s[i-1]+1.0/(i+1);   
提前把可能的结果计算了先 、、、、