汇编里的dw怎么理解??????????????
程序代码:
assume cs:code,ds:data,ss:stack data segment dw 0123h,0456h,0789h,0abch,0defh,0dedh,0cbah,0987h data ends stack segment dw 0,0,0,0,0,0,0,0 ;这段怎么理解呢?? stack ends code segment start: mov ax,stack mov ss,ax mov sp,16 mov ax,data mov ds,ax push ds:[0] push ds:[2] pop ds:[2] pop ds:[0] mov ax,4c00h int 21h code ends end startdw 这个怎么理解??在DOS怎么看呢??谢谢了