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标题:too many arguments in function call问题
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eddy22
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已结贴  问题点数:20 回复次数:3 
too many arguments in function call问题
#include "stdio.h"
#include "math.h"
#include <string.h>
#define pi 3.1415926   //contant for pi number
#define D 0.100           //cylinder bore
#define S 0.115           //cylinder stroke
#define B 18.4            //compression ratio
#define Vh 0.000903   //swept volume
#define As 0.302632    //ratio crankshaft radius versus connnecting rod length
#define p0 0.1            //atmo pres
#define n 2300           //engine speed
#define t0 288            //atmo temp
#define Hu 44100        //calorific value
#define ot 20              //temperature added to intake fresh
#define r 0.04            
#define tr 800             //
#define R 0.28708
#define m 1
#define l0 14.4
#define tw1 450
#define tw2 500
#define tw3 430
#define Nu 0.99
#define Ml 0.0007
#define Mb0 0.000025
#define Mbr 0.000001

double A,M,P[200],T[200],phi[200],Vm[200];
double qes=229;
double qvb=335;
double qve=420;
double qao=488;
int g;

double main(){
    double cv(),Vol(),dVdphi(),pres(),coeff(),dQwdphi(),dQbdphi(),Mb(),exair(),U();
    double dUdphi(),rk4(),comp(),comb(),expa(),pri();
    double tes,tvb,tve,tao;
    tes=(t0+ot+r*tr)/(1+r);
    tvb=rk4("compssion",qes,qvb,tes,5.0);
    pri();
    tve=rk4("combustion",qvb,qve,tvb,1.0);
    pri();
    tao=rk4("expansion",qve,qao,tve,5.0);
    pri();
}
// calculate transient cv
double cv(double x,double y){
    double f;
    f=-3.0*(0.0975+0.0485/pow(x,0.75))*(y-273)*(y-273)*1.e-6;
    f+=2.0*(7.768+3.36/pow(x,0.8))*(y-273)*1.e-4;
    f+=(489.6+46.4/pow(y,0.93)*1.e-2);
    f*=0.14455;
    return(f);
}

// calculate transient volume v(\phi)
double Vol(double x){
    double f;
    f=2.0/(B-1)+1-cos(x)+(1-sqrt(1-As*As*sin(x)*sin(x))/As);
    f*=Vh/2;
    return(f);
}
//calculate volume change derivative against \phi
double dVdphi(double x){
    double f;
    f=sin(x)+As*sin(x)*cos(x)/sqrt(1-As*As*sin(x)*sin(x));
    f*=Vh/2;
    return(f);
}
//calculate cylinder pressure
double pres(double x,double y){
    double f;
    f=M*R*y*0.001/Vol(x);
    return(f);
}
//calculate transient heat exchange coefficients
double coeff(double x,double y){
    double f,c1,c2,v1,cm,p1,t1;
    c1=2.28;
    c2=3.24*1.e-3;
    cm=7.0;
    p1=0.9*p0;
    v1=Vol(225*pi/180);
    t1=(t0+ot+r*tr)/(1+r);
    f=130*pow(y,-0.53);
    f*=pow(pres(x,y),0.8);
    f*=pow(D,-0.2);
    f*=pow((c1*cm+c2*Vh*t1*(pres(x,y)-p0)/p1/v1),0.8);
    f/=1000;
    return(f);
}
//calculate burnt fraction
double mb(double x){
    double f,s,h;
    s=qve-qvb;
    h=(x*180/pi-qvb)/s;
    f=Mb0*h+Mbr;
    return(f);
}
//calculate transient excess air ratio
double exair(double x){
    double f;
    f=Ml/0/mb(x);
    return(f);
}
//calculate internal energy
double U(double x, double y){
    double f;
    f=-(0.0972+0.0485/pow(exair(x),0.75))*pow((y-273),3)*1.e-6;
    f+=(7.768+3.36/pow(exair(x),0.8))*pow((y-273),2)*1.e-4;
    f+=(489.6+46.4/pow(exair(x),0.93))*(y-273)*1.e-2+1356.8;
    f*=0.14455;
    return(f);
}
//calculate partial derivative of u to excess air ratio
double dUdl(double x, double y){
    double f,u0,u1,h=0.01;
    u0=U(x,y);
    u1=U(x+h,y);
    f=(u1-u0)/h;
    return(f);
}
//calculate heat transfer per crankshaft angle
double dQwdphi(double x, double y){
    int i;
    double f=0,A[3],tw[3]={tw1,tw2,tw3};
    A[0]=3.14*D*D/4;
    A[1]=3.14*D*D/4;
    A[2]=4*Vol(x)/D;
    for (i=0;i<3;i++)
        f=f+coeff(x,y)*A[i]*(tw[i]-y)*30/(pi*n);
    return(f);
}
//calculate transient heat release rate
double dQbdphi(double x, double y){
    double f,dura;
    dura=(qve-qvb)*pi/180;
    f=6.908*Nu*Mb0*(m+1.0)*pow((x-qvb*pi/180)/dura,m);
    f*=exp(-6.908*pow((x-qvb*pi/180)/dura,(m+1.0)));
    f/=dura;
    return(f);
}
//codes for printing out step outcome
double pri(){
    int i;
    for (i=0;i<g;i++){
        FILE *fp=fopen("d:\\input.txt","a");
        printf("%c    %c(%3.0f%cCA):    %c",186,237,phi[i],248,179);
        printf("P=%5.4f MPa   %c",P[i],179);
        printf("V=%8.7f m3   %c",Vm[i],179);
        printf("T=%8.3f K   %c\n",T[i],186);
        fprintf(fp,"%4.2f(CA), %8.4F L, %8.3f MPa, %10.4f K, \n",phi[i],1000*Vm[i],P[i],T[i]);
        fclose(fp);
    }
}
//compression process
double compression(double x, double y){
    double f;
    M=Ml+Mbr;
    A=10000;
    f=dQwdphi(x, y)-pres(x, y)*dVdphi(x)*1000;
    f=f/(M*cv(x, y));
    return(f);
}
//combustion process
double combustion(double x, double y){
    double f,dmdphi,dLdphi;
    M=Ml+mb(x)+Mbr;
    A=exair(x);
    dmdphi=dQbdphi(x,y)/Hu;
    dLdphi=-Ml*dQbdphi(x,y)/(l0*Hu*mb(x)*mb(x));
    f=(dQbdphi(x,y)+dQwdphi(x,y)-1000*pres(x,y)*dVdphi(x)-U(x,y)*dmdphi-M*dUdl(x,y)*dLdphi)/(M*cv(x,y));
    return(f);
}
//expansion process
double expansion(double x, double y){
    double f;
    M=Ml+Mb0+Mbr;
    A=Ml/(l0*(Mb0+Mbr));
    f=dQwdphi(x, y)-1000*pres(x, y)*dVdphi(x);
    f=f/(M*cv(x, y));
    return(f);
}
double rk4(char *process, double qstart, double qend, double TK, double step){
    double k1,k2,k3,k4;
    int i;
    phi[0]=qstart;
    T[0]=TK;
    g=(int)(qend-qstart)/step;
    for(i=0;i<=g;i++){
        if(strcmp(process,"compression")==0){
        k1=step*compression(phi[i]*pi/180,T[i])*pi/180;
        k2=step*compression((phi[i]+step/2.0)*pi/180,(T[i]+k1/2.0))*pi/180;
        k3=step*compression((phi[i]+step/2.0)*pi/180,(T[i]+k2/2.0))*pi/180;
        k4=step*compression((phi[i]+step)*pi/180,(T[i]+k3))*pi/180;
        T[i+1]=T[i]+(k1+2*k2+2*k3+k4)/6.0;
        phi[i+1]=phi[i]+step;
        Vm[i]=Vol(phi[i]*pi/180);
        P[i]=pres(phi[i]*pi/180,T[i]);
        }
        else if(strcmp(process,"combustion")==0){
        k1=step*combustion(phi[i]*pi/180,T[i])*pi/180;
        k2=step*combustion((phi[i]+step/2.0)*pi/180,(T[i]+k1/2.0))*pi/180;
        k3=step*combustion((phi[i]+step/2.0)*pi/180,(T[i]+k2/2.0))*pi/180;
        k4=step*combustion((phi[i]+step)*pi/180,(T[i]+k3))*pi/180;
        T[i+1]=T[i]+(k1+2*k2+2*k3+k4)/6.0;
        phi[i+1]=phi[i]+step;
        Vm[i]=Vol(phi[i]*pi/180);
        P[i]=pres(phi[i]*pi/180,T[i]);
        }
        else if(strcmp(process,"expansion")==0){
        k1=step*expansion(phi[i]*pi/180,T[i])*pi/180;
        k2=step*expansion((phi[i]+step/2.0)*pi/180,(T[i]+k1/2.0))*pi/180;
        k3=step*expansion((phi[i]+step/2.0)*pi/180,(T[i]+k2/2.0))*pi/180;
        k4=step*expansion((phi[i]+step)*pi/180,(T[i]+k3))*pi/180;
        T[i+1]=T[i]+(k1+2*k2+2*k3+k4)/6.0;
        phi[i+1]=phi[i]+step;
        Vm[i]=Vol(phi[i]*pi/180);
        P[i]=pres(phi[i]*pi/180,T[i]);
        }
    }
    return(T[i]);
}
搜索更多相关主题的帖子: function include number engine versus 
2011-11-27 14:43
eddy22
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做一个模拟计算的程序
too many arguments in function call
rk4 function does not take 5 arguments 问题
code如上
2011-11-27 14:45
embed_xuel
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一点注释都没有

总有那身价贱的人给作业贴回复完整的代码
2011-11-27 17:31
cosam
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得分:10 
函数调用中参数太多。可能是函数定义中的参数定义和调用时的不一样。
还有你的宏定义过多.有些地方用const声明就好。



[ 本帖最后由 cosam 于 2011-11-27 18:09 编辑 ]
2011-11-27 18:07
快速回复:too many arguments in function call问题
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