#include <stdio.h>
double f(double a, double b, double c, double x)
{
    double n;
    n=a*x*x+b*x+c;
    return n;
}
void main()
{
    double a,b,c,x;
    printf("Please enter a: ");
    scanf("%f",&a);
    printf("Please enter b: ");
    scanf("%f",&b);
    printf("Please enter c: ");
    scanf("%f",&c);
    printf("Please enter x: ");
    scanf("%f",&x);
    printf("The polynomial %2.1fx^2+%2.1fx+%2.1f at the point x=%2.1f is %2.1f",a,b,c,x,f(a,b,c,x));
}





为什么最后运行出来的是0.0x^2+0.0x-1.&=-1.&  这样的结果？    顺便这道题有没有简便点的方法，觉得这个方法太累赘了  但是也需要用一个

#include <stdio.h>
double f(double a, double b, double c, double x)
{
    double n;
    n=a*x*x+b*x+c;
    return n;
}
void main()
{
    double a,b,c,x;
    printf("Please enter a: ");
    scanf("%Lf",&a);
    printf("Please enter b: ");
    scanf("%Lf",&b);
    printf("Please enter c: ");
    scanf("%Lf",&c);
    printf("Please enter x: ");
    scanf("%Lf",&x);
    printf("\nThe polynomial %2.1fx^2+%2.1fx+%2.1f at the point x=%2.1f is %2.1f",a,b,c,x,f(a,b,c,x));
getchar();
}

thank you   能告诉我为什么这样改吗？   还有最后的getchar我去掉之后试了一下也是可以的  为什么要加这个呢？