下面的这个程序哪里出错了，没错的话，那它的运行结果是多少？

#include<stdio.h>
                      #include<math.h>
       void main()
{   
    float a,b,c,s,area:
                      scanf(“%f ,%f, %f”,&a,&b,&c);
                      s=1.0/2*(a+b+c);

       area=sqrt(s*(s-a)*(s-b)*(s-c));

      printf(“a=%7.2f,  b=%7.2f,  c=%7.2f,  s=%7.2f\n”,a,b,c,s);

             printf(“area=%7.2f\n”,area);      
          }

#include <stdio.h>
                      #include <math.h>
       void main()
{   
    float a,b,c,s,area;
                      scanf("%f ,%f, %f",&a,&b,&c);
                      s=1.0/2*(a+b+c);

       area=sqrt(s*(s-a)*(s-b)*(s-c));

      printf("a=%7.2f,  b=%7.2f,  c=%7.2f,  s=%7.2f\n",a,b,c,s);

             printf("area=%7.2f\n",area);


   
}

部分符号没在英文下输入

#include<stdio.h>
#include<math.h>
void main()
{   
    float a,b,c,s,area;
    scanf("%f,%f,%f",&a,&b,&c);
    s=(float)(1.0/2*(a+b+c));

       area=(float)sqrt(s*(s-a)*(s-b)*(s-c));

      printf("a=%7.2f,  b=%7.2f,  c=%7.2f,  s=%7.2f\n",a,b,c,s);

             printf("area=%7.2f\n",area);      
 }

我用的是VC++6.0改的

#include<stdio.h>
                      #include<math.h>
       void main()
{   
    float a,b,c,s,area:
                      scanf(“%f %f %f”,&a,&b,&c);   你这里多了两个逗号..其它应该没有错，
                      s=1.0/2*(a+b+c);

       area=sqrt(s*(s-a)*(s-b)*(s-c));

      printf(“a=%7.2f,  b=%7.2f,  c=%7.2f,  s=%7.2f\n”,a,b,c,s);

             printf(“area=%7.2f\n”,area);      
          }

输入：45、68、78；
a=45.00,b=68.00,c=78.00;s=95.50;
area=1523.47