#include<stdio.h>
main()
{
    char *filename;
    FILE *fp1,*fp2;
    int i,number;
    fp1=fopen("TEST","w");
    for(i=1;i<=100;i+=10);
     putw(i,fp1);
     fclose(fp1);
     printf("\ninput filename\n");
open_file:
     scanf("%s",filename);
     if((fp2=fopen(filename,"r"))==NULL)
     {
         printf("cannot open the file\n\n");
         printf("type filename again\n");
         goto open_file;
     }
     else
         for(i=1;i<=100;i+=10)
         {number=getw(fp2);
         if(feof(fp2))
         {
             printf("\ran out of data\n");break;
         }
         else
             printf("%d\n",number);
         }
         fclose(fp2);
}

#include<stdio.h>
#include<stdlib.h>
int main()
{
    char *filename;
    filename = (char *) malloc (15*sizeof(char));
    FILE *fp1,*fp2;
    int i,number;
    fp1 = fopen("TEST","w");
    for(i=1;i<=100;i+=10);
    putw(i,fp1);
    fclose(fp1);
    printf("\ninput filename\n");
open_file:
     scanf("%s",filename);
     if((fp2=fopen(filename,"r"))==NULL)
     {
         printf("cannot open the file\n\n");
         printf("type filename again\n");
         goto open_file;
     }
     else
         for(i=1;i<=100;i+=10)
         {
             number=getw(fp2);
            if(feof(fp2))
            {
                printf("\ran out of data\n");
                break;
            }
            else
                printf("%d\n",number);
         }
         fclose(fp2);

    return 0;
}

    for(i=1;i<=100;i+=10);i执行完这天语句  出来就是101
    putw(i,fp1);i = 101
如果想连续的输出多个结果 1 11 21 31 41 51 61 71 81 91 就擦掉for后的";"

这是一个错误，但改了之后还是不运行。当我输完file name后，windows就出现一个对话框，说feof.exe停止工作，feof是我起的的文件名。

fp1 = fopen("TEST","w");

这个文件为什么没有后缀呢.

putw是什么库函数..

feof 是文件结束检测函数
文件 名是“TEST”

系统自建的的，可以没有

那估计是我的vc++6.0出了问题，非常感谢