TRENTE=VINGT+CINQ+CINQ；每个字母代表0-9之间不同的数字  用语言算出其中的每个数字
我编的代码如下  希望路过的朋友指点一下    谢谢
#include<stdio.h>
#include<conio.h>
 main()
{
      long V,I,N,T,E,Q,C,R,G;
      T=1;R=0;
      long VINGT,CINQ,TRENTE;
      
      long IN,sum;
      for(V=8;V<=9;V++)
         for(I=0;I<=9;I++)
           if(I!=V&&I!=T)
             for(N=0;N<=9;N++)
                if(N!=I&&N!=V&&N!=T)
                {
                                   IN=I*10+N;
                                   for(G=0;G<=9;G++)
                                     if(G!=N&&G!=I&&G!=V&&G!=T&&G!=R)
                                      for(C=2;C<=9;C++)
                                      if(C!=G&&C!=N&&C!=I&&C!=V&&C!=T&&C!=R)
                                       for(Q=2;Q<=9;Q++)
                                       if(Q!=C&&Q!=G&&Q!=N&&Q!=I&&Q!=V&&Q!=T&&Q!=R)
                                       for(E=3;E<=9;E+=2)
                                       if(E!=Q&&E!=C&&E!=G&&E!=N&&E!=I&&E!=V&&E!=T&&E!=R)
                                       {
                                           TRENTE=((((T*10+R)+E)*10+N)*10+T)*10+E;
                                           VINGT=((V*100+IN)*10+G)*10+T;
                                           CINQ=(C*100+IN)*10+Q;
                                           sum=VINGT+CINQ+CINQ;
                                           if(sum==TRENTE)
                                           {
                                                          printf("%8ld",VINGT);
                                                          printf("\n%8ld",CINQ);
                                                          printf("\n+)%6ld",CINQ);
                                                          printf("\n%8ld",TRENTE);
                                                          }}}
                                                    getch();}

你确定你排除的都对的？？怎么没答案出来的？？？

这是答案的源代码，应该不会有错  就是不排除也应该有很多答案啊  也不是没答案啊  

TRENTE=VINGT+CINQ+CINQ

这样看
一个6位数 = 一个5位数+ 两个相等的 4位数
6位数的个位 和 千位相等、 十位 和 十万位相等