#include<stdio.h>
void main
{
int x,y;
char op;
printf("inputx op y in order %d%c%d",x,op,y);
scanf("%d%c%d",x,op,y>;
switch(op)
{
 case(+)
 printf("x+y=%d",x+y); break;
 case(-)
 printf("x-y=%d",x-y); break;
}

#include<stdio.h>
void main
{
int x,y;
char op;
printf("inputx op y in order ");
scanf("%d%c%d",&x,&op,&y);
switch(op)
{
case(+)
printf("x+y=%d",x+y); break;
case(-)
printf("x-y=%d",x-y); break;
}
由于手里没工具,你先试试对不对

[[it] 本帖最后由 楚雄过客 于 2008-11-6 09:33 编辑 [/it]]

+ - ，字符啊

我刚刚试过了，还是不行，

程序存在的问题：
    输入函数scanf()格式错误，switch语句格式错误，单个字符要用一对单引号‘’括起来……
    以后多细心点吧……
#include<stdio.h>
main()
{int x,y;
 char op;
 printf("input x op y in order %d%c%d");
 scanf("%d%c%d",&x,&y,&op);
 switch(op)
   {
    case '+':
    printf("x+y=%d",x+y);
    break;
    case '-':
    printf("x-y=%d",x-y);
    break;
   }
}

这样就可以了
#include <stdio.h>
main()
{
int x,y;
char op;
printf("inputx op y in order ");
scanf("%d%c%d",&x,&op,&y);
switch(op)
{
case('+'):
printf("x+y=%d",x+y); break;
case('-'):
printf("x-y=%d\n",x-y);
}}

#include<stdio.h>
void main()
{
int x,y;
char op;
printf("inputx op y in order ",x,op,y);
scanf("%d%c%d",x,op,y);
switch(op)
{
case('+'):
printf("x+y=%d",x+y); break;
case('-'):
   printf("x-y=%d",x-y); break;
}
}

按照你说的程序通过编译了，多谢你的提醒了！

#include<stdio.h>
void main
{
int x,y;
char op;
printf("inputx op y in order %d%c%d",x,op,y);
scanf("%d%c%d",x,op,y>;
switch(op)
{
case(+)
printf("x+y=%d",x+y); break;
case(-)
printf("x-y=%d",x-y); break;
}
你的x，y，op还没有赋值，你就输出是不对的
改成
printf("inputx op y in order ");
scanf("%d%c%d",&x,&op,&y）;