#include "stdafx.h"
#include<stdio.h>
#include<malloc.h>
#define LEN sizeof(struct line)
#define NULL 0
struct line
{
    int a;
    int b;
    int c;
    struct line *next;
};
int n;

struct line *creat(void)
{
    struct line *head;
    struct line *p1,*p2;
    n=0;
    p1=p2=(struct line *)malloc(LEN);
    scanf("%d",&p1->c);
    head=NULL;
    while(p1->c!=0)
    {n=n+1;
    if(n==1)head=p1;
    else p2->next=p1;
    p1=(struct line *)malloc(LEN);
    scanf("%d",&p1->c);
    }
    p2->next=NULL;
    return(head);
}
void main()
{ line *h;
h=creat();
   while(h!=NULL)
   {printf("%d",h->c);
    h=h->next;
   }
}

为何不能将链表完全输出而是只输出第一个数??
如何才能将链表完全输出？

#include<stdio.h>
#include<malloc.h>
#define LEN sizeof(struct line)
#define NULL 0
struct line
{
    char c;
    struct line *next;
};
int n;

struct line *creat(void)
{
    struct line *head;
    struct line *p1,*p2;
    n=0;
    p2=head=(struct line *)malloc(LEN);
    printf("输入第%d个结点:",n);
    scanf("%c",&head->c);
    head->next=NULL;
    while(p2->c!='0')
    {
        n=n+1;
        p1=(struct line *)malloc(LEN);
        p2->next=p1;
        p2=p1;
        printf("输入第%d个结点:",n);
        fflush(stdin);
        scanf("%c",&p1->c);
        
    }
    p2->next=NULL;
    return head;
}
void main()
{ line *h;
  h=creat();
   while(h!=NULL)
   {printf("%c",h->c);
    h=h->next;
   }
}

为何这两个程序有不同的结果呢？

自己分析啊....

谢了