如以下两个程序:sy29.asm和sy28.asm,用存储器传递参数对吗?
(运行结果:不能传递),为什么

sy29.asm:       ;将dx,ax置数,并存入0:200h和0:202h两个字单元中,传递参数

extrn divdw:far
DATAS SEGMENT
    ;此处输入数据段代码  
DATAS ENDS

STACKS SEGMENT
    ;此处输入堆栈段代码
STACKS ENDS

CODES SEGMENT
main proc far    
    ASSUME CS:CODES,DS:DATAS,SS:STACKS
START:
    push ds
    mov ax,0
    push ax
   
    MOV AX,DATAS
    MOV DS,AX

    mov ax,0ffffh
    mov dx,0ffffh

    mov bx,0
    mov es,bx
    mov di,200h
    mov word ptr es:[di],ax
    inc di
    inc di
    mov word ptr es:[di],dx

    call far ptr divdw       ;调用divdw

    ret
main endp   
CODES ENDS
    END START




sy28.asm:                 ;从0:200h和0:202h中取出ax,dx并运算,转换为十进制数并显示


public divdw
DATAS SEGMENT
    db 100 dup(?)            ;储存转换后的十进制数
DATAS ENDS

STACKS SEGMENT
STACKS ENDS

CODES SEGMENT
divdw proc far
    ASSUME CS:CODES,DS:DATAS,SS:STACKS
START:
    MOV AX,DATAS
    MOV DS,AX
    mov si,0

    mov ax,0           ;从0:200h和0:202h中取出ax,dx
    mov es,ax
    mov di,200h

    mov ax,es:[di]
    inc di
    inc di
    mov dx,es:[di]

    mov cx,10           ;除数


lop:push bx             ;运算并储存
    mov bx,ax
    mov ax,dx
    mov dx,0
    div cx
    push ax
    mov ax,bx
    div cx
    mov ds:[si],dl
    pop dx
    pop bx
    inc si
    cmp ax,0
    jne lop


    mov ax,0b800h         ;显示
    mov es,ax
    mov di,0
    mov cx,si
    dec si
s1: mov al,ds:[si]   
    add al,30h
    mov byte ptr es:[di],al
    inc di
    inc di
    dec si
    loop s1


    ret
divdw endp   
CODES ENDS
    END START