编写一个函数，输入n为偶数时，调用函数求1/2+1/4+...+1/n,当输入n为奇数时，调用函数
　　　1/1+1/3+...+1/n
  不用指针做~~  我写到调用就紧错误 55555

#include<stdio.h>
float i;
float f=0;
float fun1(int n)
{    

    for(i=2;i<=n;i=i+2)
        f=f+1/i;
    return(f);
}
float fun2(int n)
{    

    for(i=1;i<=n;i=i+2)
        f=f+1/i;
    return(f);
}
void main()
{
    int n;
    printf("input a number:");
    scanf("%d",&n);
    if(n%2==0)
        printf("%f\n",fun1(n));
    else
        printf("%f\n",fun2(n));
}

#include "stdio.h"
double fun(int n)
{
int i;
double sum=0;
 if(n%2==0)
 for(i=2;i<=n;i+=2)
 sum+=1.0/i;
 else
 for(i=1;i<=n;i+=2)
 sum+=1.0/i;

return sum;
}
void main()
{
    int n;
   double sum;
    printf("input a number:");
    scanf("%d",&n);
   sum=fun(n);
        printf("%f\n",sum);
}