declare @xx char(20),@yy char(20) ,@zz char(20)
declare zz cursor for
select 员工号,姓名,缺勤名称 from JBQK a, QQLX b where a.缺勤类型 = b.缺勤类型 and a.缺勤天数 = 1
print '缺勤天数为1天的'
open zz
fetch next from zz into @xx,@yy,@zz
while @@fetch_status = 0
begin 
    fetch next from zz into @xx,@yy,@zz
    print '员工号'++'              '+'姓名'+'               '+'缺勤名称'
        print @xx +@yy + @zz
end
close zz

declare yy cursor for
select 员工号,姓名,缺勤名称 from JBQK a, QQLX b where a.缺勤类型 = b.缺勤类型 and a.缺勤天数 = 2
print '---------------------'
print '缺勤天数为2天的'
open yy
fetch next from yy into @xx,@yy,@zz
while @@fetch_status = 0
begin 
    fetch next from yy into @xx,@yy,@zz
    print '员工号'++'              '+'姓名'+'               '+'缺勤名称'
        print @xx +@yy + @zz
    
    
end
close yy 

结果查出来两个结果一样的

while @@fetch_status = 0
begin
        
        print '员工号'++'              '+'姓名'+'               '+'缺勤名称'
        print @xx +@yy + @zz
        fetch next from yy into @xx,@yy,@zz
        
end

--试试这样子?

declare @xx char(20),@yy char(20) ,@zz char(20)
DECLARE @INT INT,@INT2 INT
SET @INT=1
SET @INT2=1
declare zz cursor for
select 员工号,姓名,缺勤名称 from JBQK a, QQLX b where a.缺勤类型 = b.缺勤类型 and a.缺勤天数 = 1
print '缺勤天数为1天的'
open zz
fetch next from zz into @xx,@yy,@zz
while @@fetch_status = 0
begin
        
        IF @INT=1
             BEGIN
                  print '员工号'++'              '+'姓名'+'               '+'缺勤名称'
             END
        print @xx +@yy + @zz
    SET @INT=@INT+1
        fetch next from zz into @xx,@yy,@zz
end
close zz

declare yy cursor for
select 员工号,姓名,缺勤名称 from JBQK a, QQLX b where a.缺勤类型 = b.缺勤类型 and a.缺勤天数 = 2
print '---------------------'
print '缺勤天数为2天的'
open yy
fetch next from yy into @xx,@yy,@zz
while @@fetch_status = 0
begin
        
            IF @INT2=1
             BEGIN
                  print '员工号'++'              '+'姓名'+'               '+'缺勤名称'
             END
        
        print @xx +@yy + @zz
        SET @INT2=@INT2+1
        fetch next from yy into @xx,@yy,@zz
        
        
end
close yy



这样应该可以的!

谢谢两位了