输入10个数，每输入一个数就将它插入数组，并按从小到大的循序排列
#include<stdio.h>
int
main()
{
    int i=0;
    int a[10];
    void sort(int *p,int b);
    do
    {
        //get the number
        printf("please input the number:\n");
        scanf("%d",&a[i]);
        //put into the array and sort
        sort(a,i);
        i++;
    }
    while(i<10);
    //print it in right order
    for(i=0;i<10;i++)
        printf("%d\n",a[i]);
   
}
void
sort(int *p,int n)
{
    if(n>0)
    {
        int i,j;
        for(i=0;i<n;i++)
        {
            if(p[n]<p[i])
            {
                int temp;
                temp=p[n];
                for(j=n-1;j>=i;j--)
                {
                    p[j+1]=p[j];
                    p[i]=temp;
                }
                break;
            }
            
        }
    }
}
       输入9 8 7 6 5 4 3 2 1 0 输出时却是0 0  1 2 3 4 5 6 7 9
不知道错在哪里，望高手指教！谢谢!

我没有感觉你在做插入排序啊
至少一次插入过程只需一次循环.

#include<stdio.h>
int
main()
{
    int i=0;
    int a[10];
    void sort(int *p,int b);
    do
    {
        //get the number
        printf("\nplease input the %d number:" ,i);
        scanf("%d",&a[i]);
        //put into the array and sort
        sort(a,i);
        i++;
    }
    while(i<10);
    //print it in right order
    for(i=0;i<10;i++)
        printf("%d\t",a[i]);
    putchar(10);
    return 0;
   
}
void
sort(int *p,int n)
{
    int i,j;
    if(n>0)
    {
        
        for(i=0;i<n;i++)
        {
            if(p[n]<p[i])
            {
                int temp;
                temp=p[n];
                for(j=n-1;j>=i;j--)
                {
                    p[j+1]=p[j];
                    
                }
                p[i]=temp;break;
            }
            
        }
    }
    for(i=0;i<n+1;i++)
        printf("%d\t",p[i]);
}